listed below are the numbers of words spoken in a day by each member of eight different randomly selected couples. Complete parts (a) and (b) below. Male 15,071 25,527 1461 8061 18,248 15,565 13,845 25,042 Female 24,849 13,483 18,874 18,503 12,530 17,604 15,855 19,353 a. Use a 0.01 significance level to test the claim that among couples, males speak fewer words in a day than females. In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test? H0: μd ▼ greater than> not equals≠ equals= less than< nothing word(s) H1: μd ▼ less than< equals= greater than> not equals≠ nothing word(s) (Type integers or decimals. Do not round.) Identify the test statistic. t=negative (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is greater than,k less than or equal to the significance level, fail to reject or reject the null hypothesis. There is or is not sufficient evidence to support the claim that males speak fewer words in a day than females. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval is negative ???word(s)<μd?? word(s). (Round to the nearest integer as needed.) What feature of the confidence interval leads to the same conclusion reached in part (a)? Since the confidence interval contains --- fail to reject or reject the null hypothesis.
listed below are the numbers of words spoken in a day by each member of eight different randomly selected couples. Complete parts (a) and (b) below. Male 15,071 25,527 1461 8061 18,248 15,565 13,845 25,042 Female 24,849 13,483 18,874 18,503 12,530 17,604 15,855 19,353 a. Use a 0.01 significance level to test the claim that among couples, males speak fewer words in a day than females. In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test? H0: μd ▼ greater than> not equals≠ equals= less than< nothing word(s) H1: μd ▼ less than< equals= greater than> not equals≠ nothing word(s) (Type integers or decimals. Do not round.) Identify the test statistic. t=negative (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is greater than,k less than or equal to the significance level, fail to reject or reject the null hypothesis. There is or is not sufficient evidence to support the claim that males speak fewer words in a day than females. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval is negative ???word(s)<μd?? word(s). (Round to the nearest integer as needed.) What feature of the confidence interval leads to the same conclusion reached in part (a)? Since the confidence interval contains --- fail to reject or reject the null hypothesis.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter0: Preparing For Algebra
Section0.11: Simple Probability And Odds
Problem 13E
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listed below are the numbers of words spoken in a day by each member of eight different randomly selected couples. Complete parts (a) and (b) below.
Male
|
15,071
|
25,527
|
1461
|
8061
|
18,248
|
15,565
|
13,845
|
25,042
|
|
---|---|---|---|---|---|---|---|---|---|
Female
|
24,849
|
13,483
|
18,874
|
18,503
|
12,530
|
17,604
|
15,855
|
19,353
|
|
a. Use a
0.01
significance level to test the claim that among couples, males speak fewer words in a day than females.In this example,
μd
is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test?H0:
μd
nothing
word(s)▼
greater than>
not equals≠
equals=
less than<
H1:
μd
nothing
word(s)▼
less than<
equals=
greater than>
not equals≠
(Type integers or decimals. Do not round.)
Identify the test statistic.
t=negative
(Round to two decimal places as needed.)Identify the P-value.
P-value=
(Round to three decimal places as needed.)What is the conclusion based on the hypothesis test?
Since the P-value is
the significance level,
the null hypothesis. There
sufficient evidence to support the claim that males speak fewer words in a day than females.
greater than,k less than or equal to
fail to reject or reject
is or is not
b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)?
The confidence interval is
negative ???word(s)<μd<???
word(s).(Round to the nearest integer as needed.)
What feature of the confidence interval leads to the same conclusion reached in part (a)?
Since the confidence interval contains ---
the null hypothesis.
fail to reject or reject
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