M F2 124 N at a downward angle 0 You are pushing a block with force F1 from the horizontal and your friend is pulling the same block with force F2 162 N horizontally in the same direction. The block has mass m = and is moving with acceleration a in the direction of the exerted force F2. If the coefficient of kinetic friction µk : is the magnitude of acceleration ã that the block experiences? 40° 53.0 kg .250 between the block and the floor, what

College Physics
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ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter4: The Laws Of Motion
Section: Chapter Questions
Problem 30P: A block of mass m = 5.8 kg is pulled up a = 25 incline as in Figure P4.24 with a force of magnitude...
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M
//
124 N at a downward angle 0
40°
You are pushing a block with force F
from the horizontal and your friend is pulling the same block with force F2
162 N horizontally in the same direction. The block has mass m =
53.0 kg
and is moving with acceleration a in the direction of the exerted force F2. If the
coefficient of kinetic friction uk
.250 between the block and the floor, what
is the magnitude of acceleration đ that the block experiences?
Transcribed Image Text:M // 124 N at a downward angle 0 40° You are pushing a block with force F from the horizontal and your friend is pulling the same block with force F2 162 N horizontally in the same direction. The block has mass m = 53.0 kg and is moving with acceleration a in the direction of the exerted force F2. If the coefficient of kinetic friction uk .250 between the block and the floor, what is the magnitude of acceleration đ that the block experiences?
Expert Solution
Step 1

The force due to kinetic friction experienced by a body in motion is given by Ff = μkN, where

μk = coefficient of kinetic friction,

N = normal force acting on the body.

The relation between Force and acceleration experienced by a body is given by Newton's second law.

F = ma, where

m = mass of the body,

F = net force exerted on the body

a = acceleration experienced by the body.

We equate the forces in the horizontal direction and also equate the forces in the vertical direction to find the acceleration.

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