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Name: 8.A m1=2.0 kg block sides along a frictionless tabletop at v0= 8.0 m/s
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Description: 8.A m1=2.0 kg block sides along a frictionless tabletop at v0= 8.0 m/s towards a second block (at rest of mass m2=6.0 kg .A spring with spring constant K= 600 N/m is attached to the second block in such a way that is will be compressed when struck by

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Physics And Measurement

Section: Chapter Questions

Problem 26P: Review. Prove that one solution of the equation 2.00x43.00x3+5.00x=70.0 is x = 2.22.

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8.A m1=2.0 kg block sides along a frictionless tabletop at v0= 8.0 m/s towards a second block (at rest of mass m2=6.0 kg .A spring with spring constant K= 600 N/m is attached to the second block in such a way that is will be compressed when struck by the moving block .See Fig.8
(a) what will be the maximum compression of the spring ?
(b) what will be the final velocities of the block after the collision?
(c) Is the collision elastic?

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