Make a VIRP table and complete it by measuring the voltage across each resistor and the power supply and measuring the current through each resistor and the total current and the total power coming out the power supply. Set your power supply to 12 V.Provide evidence that your table information is reasonable. Write down your reasoning and show your calculations.Figure AR1 = 100 ΩR2 = 90 ΩR3 = 105 ΩNOTE: only focus in writing the reasoning of the calculations. Put them into words. Thank you! FIGURE A가R2wR3R1 Figure AR₁ =100-222= дол23= 105_2Resistors R₂ & R3 are in parallel:1 1>1Rp+F-₂73Rp1052290022p= 48.462Resistance Rp & F₁ are in seriesPetermine the equivalent resistance:Req=R₁+RpReg = 100-2 + 48.46-2Req=148-462Voltage across RiделV₁ = 1002 (12V)148.462V₁ = 8VVotage across 12 & 13:V₂ V3 = V - V₁V₂ V3 = 1₂4-81V₂ = Y3 =4V+CurrentI= Y/ReqI = 1211/ 148.462F = 0·08 Athrough the circuit:Current through 1₁:I₁= V₂/2₁F₁=811/100_02I₁= 0.08 ACurrent through R₂!√₂ | 22Іг12=4160x2I 2 = 0.044 ACurrent through 13:13 = 43/2341/10502Із=I3= 0.038 ATotal power:P= VIP= (12V) (0-08*)P = 0.96 WPower through 1₁!P₁ =V₁I₁P₁ = (8V) (0-08A)P₁ >0.64WPower through 12.₂:P₂=V₂/2P2=(44) (0.0444)P₂ = 0·176Power through 123P3 = V₁I313 = (4x) (0.038A)P320-152 W

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An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter2: Motion

Section: Chapter Questions

Problem 1FIB: An object is in motion when it undergoes a continuous change of ___. (2.1)

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Make a VIRP table and complete it by measuring the voltage across each resistor and the power supply and measuring the current through each resistor and the total current and the total power coming out the power supply. Set your power supply to 12 V. Provide evidence that your table information is reasonable. Write down your reasoning and show your calculations. Figure A R1 = 100 Ω R2 = 90 Ω R3 = 105 Ω NOTE: only focus in writing the reasoning of the calculations. Put them into words. Thank you!

Figure A
R₁ =100-2
22= дол
23= 105_2
Resistors R₂ & R3 are in parallel:
1 1
>
1
Rp
+
F-₂
73
Rp
10522
9002
2p= 48.462
Resistance Rp & F₁ are in series
Petermine the equivalent resistance:
Req=R₁+Rp
Reg = 100-2 + 48.46-2
Req=148-462
Voltage across Ri
дел
V₁ = 1002 (12V)
148.462
V₁ = 8V
Votage across 12 & 13:
V₂ V3 = V - V₁
V₂ V3 = 1₂4-81
V₂ = Y3 =4V
+
Current
I= Y/Req
I = 1211/ 148.462
F = 0·08 A
through the circuit:
Current through 1₁:
I₁= V₂/2₁
F₁=811/100_02
I₁= 0.08 A
Current through R₂!
√₂ | 22
Іг
12=4160x2
I 2 = 0.044 A
Current through 13:
13 = 43/23
41/10502
Із=
I3= 0.038 A
Total power:
P= VI
P= (12V) (0-08*)
P = 0.96 W
Power through 1₁!
P₁ =V₁I₁
P₁ = (8V) (0-08A)
P₁ >0.64W
Power through 12.₂:
P₂=V₂/2
P2=(44) (0.0444)
P₂ = 0·176
Power through 123
P3 = V₁I3
13 = (4x) (0.038A)
P320-152 W

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