Manning's equation is Q =whereCmAR 2/3 1/2nQ =Cm ==flow (m³/s)1.49 USC system1.00 SI systemroughness factor for various boundary conditionsarea (m2)hydraulic radius (m)n=A=R===S=slope of EGL (or HGL for steady uniform flow conditions) m/marea/wetted perimeterTransform the above equation to solve for pipe diameter (mm) expressed in terms of flow (L/s),pipe slope (%) and pipe roughness "n". The value of Cm 1s 1.00 for a metric equation. Expressyour answer in the simplest form mathematically. Check by assuming arbitrary values andcomparing the results between the original equation and the transformed equation.

D = 275.3317482 8/3√(Qn/S1/2)Explanation:

Answered: Manning's equation is Q = where Cm AR…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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*hydraulics *use handwritten A rectangular channel 5.50 m wide and 1.30 m deep is laid on a uniform slope of 0.002. The roughness coefficient of the channel is 0.013. 1.) Which of the following most nearly gives the rate of flow in the channel in m^3/s. Choices are A.) 21.04 B.) 13.02 C.) 1.03 D.) 22.63 E.) 0.24 F.)0.67 2.) Which of the following most nearly gives the saving’s in lining per meter length of channel that could have been offered by using the most efficient rectangular section but adhering to the same flow capacity and slope in m^2/s. Choices are A.) 21.04 B.) 13.02 C.) 1.03 D.) 22.63 E.) 0.24 F.)0.67 3.) Which of the following most nearly gives the savings in earth excavation per meter length of channel that could have been offered by using the most efficient rectangular Section but adhering to the same flow capacity and slope in m^3/s. Choices are A.) 21.04 B.) 13.02 C.) 1.03 D.) 22.63 E.) 0.24 F.)0.67
Read the question carefully and give me both a&b right solutions. A 1.3-m wide rectangular channel with a bed slope of 0.00019 has a depth of flow of 0.8m. Manning’s roughness coefficient is 0.017. (a) Can Manning’s equation be applied to this system (i.e., is the flow fully turbulent)? (b) Regardless of the answer to part a, determine the steady uniform discharge in the channel.
Show that for a hydraulically efficient rectangular channel, the flow depth is half the width of the channel. Using your answer, calculate the best hydraulic rectangular cross-section to convey Q=10m^3/s discharge with n=0.02 and S=0.0009 canal characteristics.
Fluid Mechanics question: Water flow from a pone through a 10cm diameter pipe. Find the flow rate and velocity at the outlet B. Draw the Hydraulic Grade Line and the Eneregy Grade Line for the flow from A to B.
Water is flowing uniformly in a finished-concrete channel of trapezoidal cross section with a bottom width of 0.8 m, and trapezoid angle of 50 degrees (outer angle measured from the horizontal plane). If the flow depth is measured to be 0.52 m, determine the Hydraulic Radius. a. 0.540 m b. 0.298 m c. 1.065 m d. 1.362 m
A trapezoidal channel has a bottom width of 5.0m and its sideslopes at an angle of 45o. If the depth of flow is 2.0 m calculatethe area of flow A, the wetted perimeter P, and the hydraulicradius R. If the flow is expected to be critical calculate thedischarge in the channel.
1) A triangular section has a side slope of s = 2, Manning's n = 0.02, Bottom slope of S0 = 0.005, depth, y = 2 m. Using Manning's equation (Eq. 24 in formula sheet) determine the flowrate Q. Use the Table in the last page to calculate A, and Rh (Hydraulic Radius) 2) Do the same for a rectangular section with B0 = 4 m, n = 0.015, S0 = 0.0025, and depth, y = 2 m.
Read the question carefully and give me right solution with clear calculations. At a certain location, the depth of flow in a wide rectangular channel (b y ) is 0.75 m. The channel flow rate is 1.6 m3/sec per unit width (Q/b), the bottom slope is 0.004, and Manning’s coefficient is 0.015. Determine the depth of flow 12 m downstream.
A rectangular channel is 6.3 m wide and has depth of flow of 1.7m. The slope of the channel bed is 1/1000. The material used to line the channel is known to have a Ch = 49m^(1/2) m/s. Calculate the mean velocity & discharge.
The water cross-sectional area of a culvert is 18.36 sq.m. and wetted perimeter is 12.56m. If the flow is 45.68 cu.m. per s and n=0.015, find the slope.
A compound channel in Figure Q2(b) has bottom slope of 0.6- percent . Calculate velocity and discharge of the channel if Kutter coefficient n is 0.042.
A circular concrete sewer (n=0.013) is 1.0 m in diameter and is laid on a slope of 0.005. What is its maximum flow? Select one: a. 1.84 cu.m./s b. 1.52 cu.m./s c. 2.56 cu.m./s d. 3.79 cu.m./s

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