Mass of iodovanillin = 0.1590g Vanillin mass = 0.2090g moles of iodovanillin 0.1590g/(278.04g/mol)=0.0005719 mol vanillin moles 0.2090g/(152.15g/mol)=0.001374 mol What is the theoretical yield? What is the yield percentage

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 6PS: A 0.20 mol sample of magnesium burns in air to form 0.20 mol of solid MgO. What amount (moles) of...
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Mass of iodovanillin = 0.1590g
Vanillin mass = 0.2090g
moles of iodovanillin
0.1590g/(278.04g/mol)=0.0005719 mol
vanillin moles
0.2090g/(152.15g/mol)=0.001374 mol
What is the theoretical yield?
What is the yield percentage
Transcribed Image Text:Mass of iodovanillin = 0.1590g Vanillin mass = 0.2090g moles of iodovanillin 0.1590g/(278.04g/mol)=0.0005719 mol vanillin moles 0.2090g/(152.15g/mol)=0.001374 mol What is the theoretical yield? What is the yield percentage
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