Masses M1 and M2 are supported by wires that have equal lengths when unstretched. The wire supporting M1 is an aluminum wire 1.35 mm in diameter, and the one supporting M2 is a steel wire 0.4 mm in diameter. What is the ratio M1/M2 if the two wires stretch by the same amount? Young’s modulus for aluminum is 7 × 10^10 N/m^2and for steel 2 × 10^11 N/m^2. *

icon
Related questions
icon
Concept explainers
Question
Masses M1 and M2 are supported by wires that have equal lengths when unstretched. The wire supporting M1 is an aluminum wire 1.35 mm in diameter, and the one supporting M2 is a steel wire 0.4 mm in diameter. What is the ratio M1/M2 if the two wires stretch by the same amount? Young’s modulus for aluminum is 7 × 10^10 N/m^2and for steel 2 × 10^11 N/m^2. *
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Stress and strain
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.