MasteringPhysics: HW07bMy Questions bartlebyXXCGsession.masteringphysics.com/myct/itemView?assignmentProblemID=121806539Purchase sites b BartleByPphysics homeworkAppsphysics bookin LinkedInSapling organicPt Dynamic Periodic T...SchoolPoll EverywherePHYS2110/2109-004_2019FJenniferKHW072 of 6>Circular LaunchConstants Periodic TableA ball is launched up a semicircular chute in such a way that at the top of the chute, just before itgoes into free fall, the ball has a centripetal acceleration of magnitude 2 g. (Figure 1Part AHow far from the bottom of the chute does the ball land?Your answer for the distance the ball travels from the end of the chute should contain R.View Available Hint(s)Hint 1. Speed of ball upon leaving chuteHint 2. Time of free fallHow long is the ball in free fall before it hits the ground?Express the free-fall time in terms of R and q.View Available Hint(s)Templates Symbols undo rgo Yeset keyboard shortcuts helptr=Figure

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Asked Sep 14, 2019
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MasteringPhysics: HW07
bMy Questions bartleby
X
X
C
G
session.masteringphysics.com/myct/itemView?assignmentProblemID=121806539
Purchase sites b BartleBy
Pphysics homework
Apps
physics book
in LinkedIn
Sapling organic
Pt Dynamic Periodic T...
School
Poll Everywhere
PHYS2110/2109-004_2019F
Jennifer
KHW07
2 of 6>
Circular Launch
Constants Periodic Table
A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it
goes into free fall, the ball has a centripetal acceleration of magnitude 2 g. (Figure 1
Part A
How far from the bottom of the chute does the ball land?
Your answer for the distance the ball travels from the end of the chute should contain R.
View Available Hint(s)
Hint 1. Speed of ball upon leaving chute
Hint 2. Time of free fall
How long is the ball in free fall before it hits the ground?
Express the free-fall time in terms of R and q.
View Available Hint(s)
Templates Symbols undo rgo Yeset keyboard shortcuts help
tr=
Figure
<1 of 1
Submit
Request Anewer
Hint 3. Finding the horizontal distance
The horizontal distance follows from D z(t)=In+,ntr. where
0. 0 and tr were found in Hints 1 and 2 respectively.
emgHares Symbols undo repo Teset keyboard shortcuts help
2R
D =
Submit
Request Anewer
1:58 PM
) 9/14/2019
A
N
Type here to search
а
х‑
N
о
help_outline

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MasteringPhysics: HW07 bMy Questions bartleby X X C G session.masteringphysics.com/myct/itemView?assignmentProblemID=121806539 Purchase sites b BartleBy Pphysics homework Apps physics book in LinkedIn Sapling organic Pt Dynamic Periodic T... School Poll Everywhere PHYS2110/2109-004_2019F Jennifer KHW07 2 of 6> Circular Launch Constants Periodic Table A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the ball has a centripetal acceleration of magnitude 2 g. (Figure 1 Part A How far from the bottom of the chute does the ball land? Your answer for the distance the ball travels from the end of the chute should contain R. View Available Hint(s) Hint 1. Speed of ball upon leaving chute Hint 2. Time of free fall How long is the ball in free fall before it hits the ground? Express the free-fall time in terms of R and q. View Available Hint(s) Templates Symbols undo rgo Yeset keyboard shortcuts help tr= Figure <1 of 1 Submit Request Anewer Hint 3. Finding the horizontal distance The horizontal distance follows from D z(t)=In+,ntr. where 0. 0 and tr were found in Hints 1 and 2 respectively. emgHares Symbols undo repo Teset keyboard shortcuts help 2R D = Submit Request Anewer 1:58 PM ) 9/14/2019 A N Type here to search а х‑ N о

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Expert Answer

Step 1

Given:

Centripital acceleration of the ball just before it goes into free fall = 2g

Radius of the semicircular path = R

Step 2

Calculating the velocity of the ball just befiore it goes into free fall:

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As the chute is semicireular, so the velocity the ball at the top just before free fall would be just horizontal Let the velocity of the ball just before free fall= u Centripital acceleration = " 2g (Given) R v2gR So, uн ...(1)

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Step 3

Calculating the time of the free fall:

As the ball does not have any vertical velocity just bef...

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Using 2nd equstion of motion for vertical motion of the ball 1 S tgr Substitute S 2R, u, = 0 m/s, 2R 0 gr AR (2) t=

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