Can somebody help asap please 18.8 Finding the Image for a Converging LensTo see a flower better, you hold a 6.0-cm-focal-length magnifying glass 4.0 cm from the flower. What is themagnification?PREPARE The flower is in the object plane. We use ray tracing to locate the image. Once the image distance isknown, we can use Equation 18.9 O to find the magnification.SOLVE Figure 18.38 O shows the ray-tracing diagram. The three special rays diverge from the lens, but we canuse a straightedge to extend the rays backward to the point from which they diverge. This point, the imagepoint,s'= -12 cm. From Equation 18.9 O the magnification isseen to be 12 cm to the left of the lens. Because this is a virtual image, the image distance iss'12 cm3.04.0 cmFIGURE 18.38 Ray-tracing diagram for a magnifying glass.Trace these rays backto the image location.Focal pointImage12 cm 88ObjectfASSESS The three special rays converge to a single point, and the image orientation and size in our ray-tracingdiagram match the computed magnification-the image is upright and much larger than the object-so we haveconfidence in our results. Match the answers with questions based on Example 18.8. (Hint: Be careful with signs.)v What is the object distance?A. 0v What is the image distance?B. 4.0 cmv What is the focal length of the lens?C. -6.0 cmv What is the magnification?D. 4.0 cmЕ. 12 сmF. 6.0 cmG.-3Н.З1. -12 cm

Answered: Image /qna-images/answer/0e793ee3-a16d-4d8a-873b-311521d99832.jpg

Match the answers with questions based on Example 18.8. (Hint: Be careful with signs.) v What is the object distance? v What is the image distance? v What is the focal length of the lens? v What is the magnification? A. 0 B. -4.0 cm С. -6.0 ст D. 4.0 cm E. 12 cm F. 6.0 cm G.-3 H 3

Match the answers with questions based on Example 18.8. (Hint: Be careful with signs.) v What is the object distance? v What is the image distance? v What is the focal length of the lens? v What is the magnification? A. 0 B. -4.0 cm С. -6.0 ст D. 4.0 cm E. 12 cm F. 6.0 cm G.-3 H 3

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter25: Optical Instruments

Section: Chapter Questions

Problem 23P: A biology student uses a simple magnifier to examine the structural features of an insects wing. The...

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Question

Can somebody help asap please

18.8 Finding the Image for a Converging Lens
To see a flower better, you hold a 6.0-cm-focal-length magnifying glass 4.0 cm from the flower. What is the
magnification?
PREPARE The flower is in the object plane. We use ray tracing to locate the image. Once the image distance is
known, we can use Equation 18.9 O to find the magnification.
SOLVE Figure 18.38 O shows the ray-tracing diagram. The three special rays diverge from the lens, but we can
use a straightedge to extend the rays backward to the point from which they diverge. This point, the image
point,
s'= -12 cm. From Equation 18.9 O the magnification is
seen to be 12 cm to the left of the lens. Because this is a virtual image, the image distance is
s'
12 cm
3.0
4.0 cm
FIGURE 18.38 Ray-tracing diagram for a magnifying glass.
Trace these rays back
to the image location.
Focal point
Image
12 cm 8
8
Object
f
ASSESS The three special rays converge to a single point, and the image orientation and size in our ray-tracing
diagram match the computed magnification-the image is upright and much larger than the object-so we have
confidence in our results.

Match the answers with questions based on Example 18.8. (Hint: Be careful with signs.)
v What is the object distance?
A. 0
v What is the image distance?
B. 4.0 cm
v What is the focal length of the lens?
C. -6.0 cm
v What is the magnification?
D. 4.0 cm
Е. 12 сm
F. 6.0 cm
G.-3
Н.З
1. -12 cm

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