Match the following functions with their recursive definitions. > n! n(n+1)(2n+1) 6 2n n² 1. f(0) = 1, f(n) = n × f(n − 1) - 2. f(1) = 1, f(n) = f(n − 1) + 2n – 1 3. f(0) = 1, f(n) = 2 × f(n − 1) - 4. f(1) = 1, f(n) = f(n-1) + n²
Match the following functions with their recursive definitions. > n! n(n+1)(2n+1) 6 2n n² 1. f(0) = 1, f(n) = n × f(n − 1) - 2. f(1) = 1, f(n) = f(n − 1) + 2n – 1 3. f(0) = 1, f(n) = 2 × f(n − 1) - 4. f(1) = 1, f(n) = f(n-1) + n²
Chapter3: Functions
Section3.1: Functions And Function Notation
Problem 92SE: Show that the function f(x)=3(x5)2+7 is not one-to-one.
Related questions
Question
![Match the following functions with their recursive definitions.
<
n!
n(n+1)(2n+1)
6
2n
n²
1. f(0) = 1, f(n) =n× f(n − 1)
-
2. f(1) = 1, f(n) = f(n − 1) + 2n − 1
-
3.
f(0) = 1, f(n) = 2 × f(n − 1)
-
4. f(1) = 1, ƒ(n) = f(n − 1) + n²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c4edb98-69de-41ca-82a1-574ea53bda76%2F5ede7e9a-1fa6-4711-9f97-f1f139f12685%2Fa3r5w2i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Match the following functions with their recursive definitions.
<
n!
n(n+1)(2n+1)
6
2n
n²
1. f(0) = 1, f(n) =n× f(n − 1)
-
2. f(1) = 1, f(n) = f(n − 1) + 2n − 1
-
3.
f(0) = 1, f(n) = 2 × f(n − 1)
-
4. f(1) = 1, ƒ(n) = f(n − 1) + n²
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