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- C++ ONLY Add the following functions to the linked list. int getSize() -> This function will return the number of elements in the linked-list. This function should work in O(1). For this keep track of a size variable and update it when we insert a new value in the linked-list. int getValue(index) -> This function will return the value present in the input index. If the index is greater or equal to the size of the linked-list return -1. void printReverse() -> This function will print the linked list in reverse order. You don’t need to reverse the linked list. Just need to print it in reverse order. You need to do this recursively. You cannot just take the elements in an array or vector and then print them in reverse order. void swapFirst() -> This function will swap the first two nodes in the linked list. If the linked-list contains less than 2 elements then just do nothing and return. To check your code add the following code in your main function. LinkedList l;…Given the following list { 10,9,-2,1}, sort the list using selection sort and fill out the following table. static void selectionSort(double [] list) {// find minimum in the list [i....list.length-1]for (int i=0;i<list.length;i++) {double currentMin=list[i];int currentMinIndex=i;for (int j=i+1;j<list.length;j++) {if (currentMin>list[j]){currentMin=list[j];currentMinIndex=j;}}// j for// swap list[i] with list[currentMindIndex ifnecessary.if (currentMinIndex!=i) {list[currentMinIndex]=list[i];list[i]=currentMin;}// if}// for}1. Write a function invert_dict to reverse a dictionary, for example: >>> eng2sp = {'one': 'uno', 'two': 'dos', 'three': 'tres'} >>> sp2eng = invert_dict(eng2sp) >>> sp2eng {'uno':'one', 'dos':'two', 'tres':'three'} 2. Write a function print_dict to print all the key-values in a dictionary, for example: >>> d2 {'a': 'one', 'b': 'two', 'c': 'Three'} >>> print_dict(d2) a:one b:two c:Three
- An array may contain multiple duplicate values, as shown below. In order to design an algorithm with the best average performance to remove all duplicate values, which of the following data structures should be used? 110, 1100, s, 10, s6, s, 96, 34, s, 34, 20, 110, 30 Question 16 options: hash table stack list priority queue????????: Consider this following dictionary of lists for your question. So just copy this dictionary to your editor. number_lists = {1: [2,6,4], 2: [51,6,89], 3: [23,9,32], 4: [31,53,8], 5: [7,44,55]} Take an integer from the user (The number should be greater than 0), add up all the digits. If the summation of all the digits is even then find the summation of all the even values of all the odd keys from the given dictionary. If the summation is odd then find the summation of all the odd values of all the even keys from the given dictionary. Then print the summation. Sample Input 1: 441 Sample Output 1: 224 Explanation 01: The summation of digits of given input is 4+4+1 = 9 which is an odd number. That’s why we need to find the even keys from the dictionary which are {2: [51,6,89], 4: [31,53,8] } and sum up the odd values from these even keys which results in 51+89+31+53 = 224. Sample Input 2: 88 Sample Output 2: 88 Explanation 02: The summation of digits of given…????????: Consider this following dictionary of lists for your question. So just copy this dictionary to your editor. number_lists = {1: [2,6,4], 2: [51,6,89], 3: [23,9,32], 4: [31,53,8], 5: [7,44,55]} Take an integer from the user (The number should be greater than 0), add up all the digits. If the summation of all the digits is even then find the summation of all the even values of all the odd keys from the given dictionary. If the summation is odd then find the summation of all the odd values of all the even keys from the given dictionary. Then print the summation. Sample Input 1: 441 Sample Output 1: 224 Explanation 01: The summation of digits of given input is 4+4+1 = 9 which is an odd number. That’s why we need to find the even keys from the dictionary which are {2: [51,6,89], 4: [31,53,8] } and sum up the odd values from these even keys which results in 51+89+31+53 = 224. Sample Input 2: 88 Sample Output 2: 88 Explanation 02: The summation of digits of given…
- Write the following function that sorts and merges two lists into a new sorted list. The new list contains only even numbers. def myMergeEvenList(list1, list2): Enter list1: 10,5,6,7 Enter list2: 12,8,5,0,1 The merged list is: 0,6,8,10,12Implement the following: Given: names = ['ann', 'bill', 'calvin', 'david']ids = [12, 34, 56, 78] 1) Create a dictionary, stuInfo by using the two given lists above.2) Use a loop to print all keys and values in the dictionary stulfno. 3) Print the dictionary, stuInfo. Example Output12 ANN34 BILL 56 CALVIN78 DAVID{'ann': 12, 'bill': 34, 'calvin': 56, 'david': 78} NEED HELP WITH PYTHONConsider the following linked list while answering the questions given below. Suppose a node contains two parts that is data and next. Write statements to do the following, Update B so it will refer to the last node in the list. Set the value of the node containing 16 to 71. Create and insert the node with info 10 after the node pointed to by A.
- q9) In which of the following linked list there will be no beginning and ending? a. Depends on the Problem. b. Single Linked List. c. Double Linked List. d. Circular Linked List.Considering all the elements and its indexes at the right side:Write a sequence of List operations that would result to a LIST that contains ONLY the elements with its respective indexes: {index[00]=104, index[01]=165, index[02]=115, index[03]=384, index[04]=248, index[05]=117}.Assume the list L has the integer items {10, 20, 30} and send to the following function void do(list<int>&L){ int item, x=L.size(); for(int i=0;i<x;i++) { L.retrieve(i,item); L.insert(L.size(),item); L.remove(i);} } The list L becomes a. 10, 20, 30 b. 20, 30, 10 c. 20, 10, 30 d. 30, 20, 10