Which of the following is true about the insertBeforeCurrent function for a Circular
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True/False
Select true or false for the statements below. Explain your answers if you like to receive partial credit.
3) Which of the following is true about the insertBeforeCurrent function for a Circular
Linked List (CLL) like you did in
a. If the CLL is empty, you need to create the new node, set it to current, and
have its next pointer refer to itself
b. The worst case performance of the function is O(n)
c. If you insert a new element with the same data value as the current node, the
performance improves to O(log n)
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- Merge2AscListsRecur that combines the nodes in X-list and Y-list into Z-list such that, after calling the function, Z-list is a sorted list (in non-decreasing order) containing all the nodes initially contained in X-list and Y-list – X-list and Y-list should both be empty after the call. The function should: ► Have only three parameters (each a pointer-to-Node) and no return value (be a void function). ► Not use any global variables or static local variables. ► Not use any looping constructs (for, while, do-while, ...). ► Be directly (not indirectly) recursive. ► Not create any new nodes, destroy any existing nodes or copy/replace the data item of any node. ► Not make temporary copies of the data involved using any other storage structures (arrays, stacks, queues, etc.). ► Use (if ever needed) no more than a small number of pointers to hold certain link addresses. ○ Not make temporary copies of the…Implement the function below void swap(int pos1, int pos2) {} For LinkedList, to maintain integrity of data in the structure, you are not to swap directly the element, nor remove a node. Instead, you are to only change the nodes' next pointers. Inital code to be completed: class LinkedList : public List { node* head; node* tail; int index; node* create_node(int num) { node* n = (node*) malloc(sizeof(node)); n->element = num; n->next = NULL; return n; } public: LinkedList() { index = 0; head = NULL; tail = NULL; } int add(int num) { addTail(num); return index; } int get(int pos) { node* currnode = head; int count =0; while (currnode != NULL){ count++; if (count == pos){ return currnode -> element; }else{ currnode = currnode -> next; } }…Please implement this function: void swap(int pos1, int pos2) {}. There's an answer from the previous teacher but he added '' node** hRef " in the function (see below) please correct without the href. For LinkedList, to maintain integrity of data in the structure, you are not to swap directly the element, nor remove a node. Instead, you are to only change the nodes' next pointers. PLEASE CORRECT THIS ONE void swap(node** hRef, int pos1, int pos2) { if (pos1 == pos2) return; node *prevNode1 = NULL; node* currNode1 = *hRef; while (currNode1 && currNode1->index != pos1) { prevNode1 = currNode1; currNode1 = currNode1->next; } node *prevNode2 = NULL; node *currNode2 = *hRef; while (currNode2 && currNode2->index != pos2) { prevNode2 = currNode2; currNode2 = currNode2->next; } if (currNode1 == NULL || currNode2 == NULL) return; if (prevNode1 != NULL) prevNode1->next =…
- Suppose you have two objects of Doubly Linked List D1 and D2. Each object is representing a different Doubly Linked List. Write a function to concatenate both doubly linked lists. The concatenation function must return the address of head node of concatenated Doubly Linked List, and it must take two Node* parameters. You need to keep in mind all exceptional cases for example what if either one of the doubly linked lists is empty? Perform this task on paper, take a clear picture of solution and paste it in answer section.You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Function Description Complete the insertNodeAtTail function in the editor below. insertNodeAtTail has the following parameters: SinglyLinkedListNode pointer head: a reference to the head of a list int data: the data value for the node to insert Returns SinglyLinkedListNode pointer: reference to the head of the modified linked list Input Format The first line contains an integer , the number of elements in the linked list.The next lines contain an integer each, the value that needs to be inserted at tail. Constraints Sample Input STDIN Function ----- -------- 5 size of linked list n = 5 141 linked list data values…1. Suppose you have already developed an SLL ADT. You have to search a specificelement of the linked list. If you find the element in the list then you have to swapits previous node with its next node. Otherwise, simply print the message “Datanot found”. Now write a function in your SLL ADT with this functionality.
- Please fill in the blanks for C /* This program will print students’ information and remove students using linked list: */ #include<stdio.h> #include<stdlib.h> //Declare a struct student (node) with 5 members //each student node contains an ID, an age, graduation year, // 1 pointer points to the next student, and 1 pointer points to the previous student. struct student { int ID; int age; int classOf; __1__ __2__ next; __3__ __4__ prev; }; /* - This function takes the head pointer and iterates through the list to get all 3 integers needed from the user, and save it to our list - Update the pointer to point to the next node. */ __5__ scanLL(__6__ __7__ head) { while(__8__ __9__ __10__) //this condition makes sure the list is not at the end { printf("Lets fill in the information. Enter 3 integers for the student's ID, age, and graduation year: ");…Use the following code which adds, searches and prints elements of a doubly linked list, and add a member function that will union 2 doubly linked lists and store the union elements in a new list. Call your function properly in main and print all 3 lists. Note: You can consider that each list is a set, where no redundant elements are found. #include <iostream> using namespace std; struct node { int data; node *next,*prev; node(int d,node*n=0,node *p=0) { data=d; next=n; prev=p; } }; class list { node *head; public: list() { head=0; } void print() { for (node *t=head;t!=0;t=t->next) cout<<t->data<<" "; cout<<endl; } bool search(int el) { for (node *t=head;t!=0;t=t->next) if(t->data==el) return true; return false; } void add(int el) { if(head==0) head=new node(el); else { node *t=head; for(;t->next!=0;t=t->next); t->next=new node(el,0,t); } } }; void main() { list l1,l2,l3; l1.add(0); l1.add(7);…Can someone help me with this? C++ programming please! Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the…
- TRUE or FALSE? Answer the following question and state the reason why: The delete operation only involves the removing of the node from the list without breaking the links created by the next node. You need an array to represent each node in a linked list. STL lists are also efficient at adding elements at their back because they have a built-in pointer to the last element in the list. A circular linked list has 2 node pointers. cout<<list.back()<<endl; = The back member function returns a reference to the last element in the list. In a Dynamic Stack, the pointer top stays at the head after a push operation. During a Pop operation in Static Stack, the elements are being moved one step up. In a dynamic implementation of stack, the pointer top has an initial value of null. In a dynamic stack, the node that was popped is deleted. In a dynamic stack, the pointer top stays at the head after push operation. STL function top returns a reference to element at the top of the…Write a function that changes the places of the first and second nodes of a linked list. I.e. the First node will become the second node, and the second node will become the first node. THE FUNCTION WILL NOT EXCHANGE DATA, IT WILL CHANGE LINKS.struct node{int num;node *next, *before;};start 18 27 36 45 54 63 The above-linked list is made of nodes of the type struct ex. Your task is now to Write a complete function code to a. Find the sum of all the values of the node in the linked list. b. Print the values in the linked list in reverse order. Use a temporary pointer temp for a and b. i dont need a full code just the list part