Math PracticeWhen we deal with really big numbers, we often use scientific or engineering notation. It's allabout counting how many digits are before or after the decimal point. For example:1,000 1x103 scientific notation 1E3 engineering notation 1EE3 (which is what you have topunch into many calculators)Warning: make sure that your calculator is using either the big E or EE, and not the little e!Your calculator also should understand that 10E2 1E3 1000.25,000 2.5x104 2.5E4 = 25E3Wolt0.0034 3.4x103 = 3.4E-3 Negative powers are for numbers smaller than one!Now do the following calculations.VT1012 x 10-104.w1012 10-105.2x10-12 x 3x1010=5.6. 8x1013 2x106

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Asked Sep 19, 2019
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Math Practice
When we deal with really big numbers, we often use scientific or engineering notation. It's all
about counting how many digits are before or after the decimal point. For example:
1,000 1x103 scientific notation 1E3 engineering notation 1EE3 (which is what you have to
punch into many calculators)
Warning: make sure that your calculator is using either the big E or EE, and not the little e!
Your calculator also should understand that 10E2 1E3 1000.
25,000 2.5x104 2.5E4 = 25E3
Wolt
0.0034 3.4x103 = 3.4E-3 Negative powers are for numbers smaller than one!
Now do the following calculations.
VT
1012 x 10-10
4.
w
1012 10-10
5.
2x10-12 x 3x1010=
5.
6. 8x1013 2x106
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Math Practice When we deal with really big numbers, we often use scientific or engineering notation. It's all about counting how many digits are before or after the decimal point. For example: 1,000 1x103 scientific notation 1E3 engineering notation 1EE3 (which is what you have to punch into many calculators) Warning: make sure that your calculator is using either the big E or EE, and not the little e! Your calculator also should understand that 10E2 1E3 1000. 25,000 2.5x104 2.5E4 = 25E3 Wolt 0.0034 3.4x103 = 3.4E-3 Negative powers are for numbers smaller than one! Now do the following calculations. VT 1012 x 10-10 4. w 1012 10-10 5. 2x10-12 x 3x1010= 5. 6. 8x1013 2x106

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Step 1

As per norms, the first three questions are answered. Problem is concerned with calculation with large exponents (to base 10)

Step 2
410 x10-102-1=10 =100
12-10
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410 x10-102-1=10 =100 12-10

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Step 3
5)10 +100= 1E12
(1010 is so small,that it is negligible)
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5)10 +100= 1E12 (1010 is so small,that it is negligible)

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