Do number 3 D. acceleration due to gravity and the length of the pendulumMathematically, the period of a pendulum for small angles is expressed by theequation below.3.T = 2TLTo solve for g in the equation above, the correct rearrangement of the formula isT.A. g =2nB. g =T2T2C. g 2n1T'LD. g =47s 20

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Answered: Mathematically, the period of a…

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter14: Vibrations And Waves

Section14.1: Periodic Motion

Problem 12SSC

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Explain in terms of energy how dissipative forces such as friction reduce the amplitude of a harmonic oscillator. Also explain how a driving mechanism can compensate. (A pendulum clock is such a system.)
Suppose the length of a clock’s pendulum is changed by 1.000%, exactly at noon one day. What time will it read 24.00 hours later, assuming it the pendulum has kept perfect time before the change? Note that there are two answers, and perform the calculation to four—digit precision.
Pendulum clocks are made to run at the correct rate by adjusting the pendulum's length. Suppose you move from one city to another where the acceleration due to gravity is slightly greater, taking your pendulum clock with you, will you have to lengthen or shorten the pendulum to keep the correct time, other factors remaining constant? Explain your answer.
A vertical spring stretches 3.9 cm when a 10.-g object is hung from it. The object is replaced with a block of mass 25 g that oscillates up and down in simple harmonic motion. Calculate the period of motion.
(a) A pendulum that has a period of 3.00000 s and that is located where the acceleration due to gravity is 9.79m/s2 is moved to a location where it the acceleration due to gravity is 9.82m/s2. What is its new period? (b) Explain Why so many digits are needed in the value for the period, based on the relation between the period and the acceleration due to gravity.
What is the leng1h of a pendulum that has a period of 0.500 s?
Suppose you have a 0.750kg object on a horizontal surface connected to a spring that has a force constant of 150N/m. There is simple friction between me object and surface with a static coefficient of friction =0.100. (a) How far can the spring be stretched without moving the mass? (b) If the object is set into oscillation with an amplitude twice the distance found in part (a), and me kinetic coefficient of friction is k=0.0850, what total distance does it travel before stopping? Assume it starts at me maximum amplitude.
A vertical spring stretches 3.9 cm when a 10-g object is tiling from it. The object is replaced with a block of mass 25 g (hat oscillates up and down in simple harmonic motion. Calculate the period of motion.
The grandfather clock in the opening storyline depends on the period of a pendulum to keep correct time. (i) Suppose the clock is calibrated correctly and then a mischievous child slides the bob of the pendulum downward on the oscillating rod. Does the grandfather clock run (a) slow, (b) fast, or (c) correctly? (ii) Suppose a grandfather clock is calibrated correctly at sea level and is then taken to the top of a very tall mountain. Does the grandfather clock now run (a) slow, (b) fast, or (c) correctly?
A simple pendulum can be modeled as exhibiting simple harmonic motion when is small. Is the motion periodic when is large?
If a pendulumdriven clock gains 5.00 s/day, what fractional change in pendulum length must be made for it to keep perfect time?
You attach an object to the bottom end of a hanging vertical spring. It hangs at rest alter extending the spring 18.3 cm. You then set the object vibrating. (a) Do you have enough information to find its period? (b) Explain your answer and state whatever you can about its period.

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Mathematically, the period of a pendulum for small angles is expressed by the equation below. T = 2n, To solve for g in the equation above, the correct rearrangement of the formula is T. A. g= %3D 4T L В. g %3D C. g 2n1 %3D T2L D. g = %3D