Meal + w = 327.9g 15.4g Thot = 100.0 oC M Tcool = 20.1 oC cal 312.5g 772.2g Mw Trinal = 40.4 o C M. sam

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter17: Energy In Thermal Processes: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 81P
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Question

calculate for the specific heat with the given information 

Data:
Mcal
327.9g
Thot
100.0 oC
+ W
15.4g
Tcool = 20.1 oC
%3D
cal
312.5g
772.2g
Mw
Tfinal = 40.4 oC
M
sam
Analysis:
Finding the specific heat by the method of mixtures assumes that the energy lost by the cooling
metal is gained by the water as the mixture comes to thermal equilibrium. The energy gained by
the styrofoam cup is assumed to be negligible. Energy lost to the surroundings can also be
ignored if the experiment is carried out correctly and quickly.
Therefore: Quantity of energy lost by the sample = Quantity gained by water.
%3D
(Msam)(Csam)(Thot- Trinal) = (Mwater)(Cwater) (Tfinal – Tcool)
C.
water
= 1cal/go C
Use your data, algebra, and the above equation to find the specific heat of the sample in cal/go C.
Show your work below.
= [(Mwater) (1cal/go C) (T final
-T cold)]/ [(M am) (T hot -T final )] =
sam
Transcribed Image Text:Data: Mcal 327.9g Thot 100.0 oC + W 15.4g Tcool = 20.1 oC %3D cal 312.5g 772.2g Mw Tfinal = 40.4 oC M sam Analysis: Finding the specific heat by the method of mixtures assumes that the energy lost by the cooling metal is gained by the water as the mixture comes to thermal equilibrium. The energy gained by the styrofoam cup is assumed to be negligible. Energy lost to the surroundings can also be ignored if the experiment is carried out correctly and quickly. Therefore: Quantity of energy lost by the sample = Quantity gained by water. %3D (Msam)(Csam)(Thot- Trinal) = (Mwater)(Cwater) (Tfinal – Tcool) C. water = 1cal/go C Use your data, algebra, and the above equation to find the specific heat of the sample in cal/go C. Show your work below. = [(Mwater) (1cal/go C) (T final -T cold)]/ [(M am) (T hot -T final )] = sam
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