Question
Asked Sep 22, 2019
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Mean Temperature Difference in an Exchanger. A 1-2 exchanger with one shell
pass and two tube passes is used to heat a cold fluid from 37.8°C to 121.1°C by using
a hot fluid entering at 315.6°C and leaving at 148.9°C. Calculate the ATm and the
mean temperature difference AT in K.
oala
Ans.
m
ATim 148.9 K, ATm=131.8 K
Inrner& Row, Publishers,
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Mean Temperature Difference in an Exchanger. A 1-2 exchanger with one shell pass and two tube passes is used to heat a cold fluid from 37.8°C to 121.1°C by using a hot fluid entering at 315.6°C and leaving at 148.9°C. Calculate the ATm and the mean temperature difference AT in K. oala Ans. m ATim 148.9 K, ATm=131.8 K Inrner& Row, Publishers,

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Expert Answer

Step 1

Calculate the logarithmic mean temperature difference.

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(ThoutTem)-(Thm=Tot c.out cin h,in ΔΤ, im Th.out -T T Tout C,in h,in C,out (148.9 -37.8) -(3 15.6 -121.1) 148.9 37.8 In 315.6 121.1 =148.9 K

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Step 2

Find the dimensionless ratios Y and Z.

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Y = ^c,out Т. C,in h,in~T C,in 121.1-37.8 315.6 37.8 -0.299856 Т — Т, Z =_hin hout C,out Cin 315.6 148.9 121.1-37.8 = 2.0012

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Step 3

Obtain the correction factor corresponding to the values of ...

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F 0.885

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