MECHANICAL PENCIL/ERASERx2a. y8+x2x3+x2-xb. y11x2+110. Three thousand feet of chain link fence will be used to construct six cages Ior ashown below. Find the dimensions that maximize the enclosed area A. What is the largestpossible area? (Hint: First express y as a function of x, and then express A as a function of x.)SUG1: sug nen eTuu11. Find the point on the graph of ythat is closest to the point (4, 0).12. An open box with a rectangular base is to be constructed from a rectangular piece of cardboard16 inches wide and 21 inches long by cutting a square from each corner and then bending upthe resulting sides. Find the size of the corner square that will produce a box having the largestpossible volume.13. A metal cylindrical container with an open top is to hold 8 cubic foot. Find the dimensions thatrequire the least amount of material.14. Use the Extreme Value Theorem (EVT) to find the absolute maximum and absolute minimumvalues of the function f(x)=x+ cos 2x on the interval 0,7Tx+115. Show that the function f(x) = satisfies the hypotheses of the Mean Value Theorem on theI-xinterval -2,-1, and then find a number c in (-2,-1) that satisfies its conclusion.

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Asked Nov 11, 2019
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I need help with number 13. Thanks 

MECHANICAL PENCIL/ERASER
x2
a. y
8+x
2x3+x2-x
b. y
11
x2+1
10. Three thousand feet of chain link fence will be used to construct six cages Ior a
shown below. Find the dimensions that maximize the enclosed area A. What is the largest
possible area? (Hint: First express y as a function of x, and then express A as a function of x.)
SUG
1: sug nen e
Tuu
11. Find the point on the graph of y
that is closest to the point (4, 0).
12. An open box with a rectangular base is to be constructed from a rectangular piece of cardboard
16 inches wide and 21 inches long by cutting a square from each corner and then bending up
the resulting sides. Find the size of the corner square that will produce a box having the largest
possible volume.
13. A metal cylindrical container with an open top is to hold 8 cubic foot. Find the dimensions that
require the least amount of material.
14. Use the Extreme Value Theorem (EVT) to find the absolute maximum and absolute minimum
values of the function f(x)=x+ cos 2x on the interval 0,7T
x+1
15. Show that the function f(x) = satisfies the hypotheses of the Mean Value Theorem on the
I-x
interval -2,-1, and then find a number c in (-2,-1) that satisfies its conclusion.
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MECHANICAL PENCIL/ERASER x2 a. y 8+x 2x3+x2-x b. y 11 x2+1 10. Three thousand feet of chain link fence will be used to construct six cages Ior a shown below. Find the dimensions that maximize the enclosed area A. What is the largest possible area? (Hint: First express y as a function of x, and then express A as a function of x.) SUG 1: sug nen e Tuu 11. Find the point on the graph of y that is closest to the point (4, 0). 12. An open box with a rectangular base is to be constructed from a rectangular piece of cardboard 16 inches wide and 21 inches long by cutting a square from each corner and then bending up the resulting sides. Find the size of the corner square that will produce a box having the largest possible volume. 13. A metal cylindrical container with an open top is to hold 8 cubic foot. Find the dimensions that require the least amount of material. 14. Use the Extreme Value Theorem (EVT) to find the absolute maximum and absolute minimum values of the function f(x)=x+ cos 2x on the interval 0,7T x+1 15. Show that the function f(x) = satisfies the hypotheses of the Mean Value Theorem on the I-x interval -2,-1, and then find a number c in (-2,-1) that satisfies its conclusion.

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Expert Answer

Step 1

Solution to question number 13

Given,

            A metal cylindrical container with an open top is to hold 8 cubic foot.

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πr?h So, Volume of the cylinder, V . πr2h= 8 8 h = TTr Since, the top of the cylinder is open. So, surface area of the cylinder, S 2πrh + πr? . S=2πrh + πη2 8 S 2nr + πr2 Jur2 16 S = +πr2 r

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Step 2

Now, differentiating S with respect to t, we get

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16 ds dt dt 16 2ur r2 + 2πr d. Now, equating 0, we get dt ds = 0 dt 16 2r 0 r2 16 -2r r2 8 = nr r2 11

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Step 3

Further calcu...

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8 3 r= 2 3 r = 2 3TT 8 2 2 2 2 Then h 1 2 2 VIT (n)1- π(τ)3 (n)3 TT 4TT

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