Meżnitude of fotal acceleration
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- sdasOne morning, Cfonnie walks from her house to go to a store that is 500 ft, S 40o W from her house. She starts walking 120 ft, SW; then continues walking 100 ft, 10o S of E; then sees a friend who is 700 ft, 30o N of E from where she is. What is her friend’s location, (magnitude and direction) relative to her house? (Ans. 667.54 ft, 21.79o N of E)show complete solution and diagramsAt the top A of the vehicle moving along line AC in the figureIts speed is 30 m / sec and its weight is 9 kN.Tool radius of curvature 40The reaction force to the tires when reaching point B, which is m,and so that the tires do not separate from the asphalt when it reaches point CWhat should be the radius of curvature of point C? (hA = 6 m andhC = 9 m)This is a dynamics question. I made a mistake submitting it last time. Hint: vB=0.6 m/s down, aB=1.84 m/s2, theta=60.6 deg downward from +x-axis
- Determine the angular velocity, in rpm, of the rotating drum which results in loss of contact between the clothes and the drum at 1.0239 rad. Assume that the small vanes prevent slipping until loss of contact. Round your answer to 2 decimal placesExample] The two ends of bar AB slides along the vertical and horizontal surfaces. MA = 1,, MB = 1,0 = ot(@= const.) Determine the motion equation, the magnitude of the velocity and acceleration for point M. BThe disk in Figure, rotates about a fixed axis throughO with angular velocity ω =5 rad/sec and angularacceleration α = 3 rad/sec2in the directions shown at acertain instant. The small sphere A moves in the circularslot, and at the same instant, β = 30°, ?̇ = 2rad/sec, and?̈ = - 4 rad/sec2. Determine the absolute velocity andacceleration of A at this instant.
- angular velocity is v = 100 (4 + t) rad/s.A rigid bar is moving along two perpendicular walls. The length of the bar is LAB=1.0m. At an instant, velocity at point A is VA=1.0 m/s downward. The angle between the bar and the vertical wall is θ=30°. (1) Determine the IC (instantaneous center of zero velocity) center________ A. Point B B. Point C C. Point G D. Point OAnswer: θP = 5.16 revolutions, T = 195.306 N
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