mistry 2SO2 (g) + 02(g) = 2S03(g) Kc = 6.1 x 104 at 750K. At equilibrium PSO2 = 1. 22 bar and PO2 = 2. 33 bar what is pSO3 at 750K (convert Kc to Kp first) what is Kc at 550K is ArHo = -197.8 kJ mol -1 does decrease in temp favor products or reactants at equilibrium?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 102QRT
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Chemistry
2502 (g) + 02(g) = 2S03(g) Kc = 6.1 x 104 at
750K. At equilibrium PSO2 = 1. 22 bar and
PO2 = 2. 33 bar
what is pSO3 at 750K (convert Kc to Kp first)
what is Kc at 550K is ArHo = -197.8 kJ mol
-1
does decrease in temp favor products or
reactants at equilibrium?
Transcribed Image Text:Chemistry 2502 (g) + 02(g) = 2S03(g) Kc = 6.1 x 104 at 750K. At equilibrium PSO2 = 1. 22 bar and PO2 = 2. 33 bar what is pSO3 at 750K (convert Kc to Kp first) what is Kc at 550K is ArHo = -197.8 kJ mol -1 does decrease in temp favor products or reactants at equilibrium?
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