Moose 1 2 3 4 5 6 xa: WOLVES ABSENT Fat (x) 43 49 14 57 31 19 35.5 x-xa (x-x₂)² Moose 7.5 56.25 13.5 -21.5 21.5 -4.5 182.25 462.25 o a: 462.25 20.25 -16.5 272.25 Sum of squared differences: 1455.5 1 2 3 4 5 6 xp: WOLVES PRESENT Fat (x) 76 68 52 38 62 81 62.8

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter19: Population Genetics And Human Evolution
Section: Chapter Questions
Problem 10QP
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Question
Moose
1
2
3
4
5
6
xa:
WOLVES ABSENT
Fat (x)
43
49
14
57
31
19
35.5
x-xa (x-x₂)² Moose
7.5
56.25
13.5
-21.5
21.5
-4.5
182.25
462.25
o a:
462.25
20.25
-16.5 272.25
Sum of squared differences: 1455.5
1
2
3
4
5
6
WOLVES PRESENT
Fat (x)
76
68
52
38
62
81
¯p: 62.8
Transcribed Image Text:Moose 1 2 3 4 5 6 xa: WOLVES ABSENT Fat (x) 43 49 14 57 31 19 35.5 x-xa (x-x₂)² Moose 7.5 56.25 13.5 -21.5 21.5 -4.5 182.25 462.25 o a: 462.25 20.25 -16.5 272.25 Sum of squared differences: 1455.5 1 2 3 4 5 6 WOLVES PRESENT Fat (x) 76 68 52 38 62 81 ¯p: 62.8
M
3
0²/12
Here, na
(sum of squared differences),
na - 1
is the number of moose sampled from the
population with wolves absent.
Estimate the variance in moose fat stores (WOLVES
ABSENT). To do this, divide the Sum of squared
differences by the sample size minus one (na-1).
Enter this value in the bottom row of the left half of the
table.
Q4.10. Make sure you're on track. What is your
estimated variance for fat stores with wolves
absent?
Check Answer
Transcribed Image Text:M 3 0²/12 Here, na (sum of squared differences), na - 1 is the number of moose sampled from the population with wolves absent. Estimate the variance in moose fat stores (WOLVES ABSENT). To do this, divide the Sum of squared differences by the sample size minus one (na-1). Enter this value in the bottom row of the left half of the table. Q4.10. Make sure you're on track. What is your estimated variance for fat stores with wolves absent? Check Answer
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