Multiply (3 - 4i)(2 + 5i).

Q: (6+3i)(6-3i)

A: topic - multiplication of complex numbers

Q: Calculate: 4+ 3i (a) -1- 3i (b) (1 + i)(3 – 4i)(4 – i) = i(2 + 2i)³ | (c) (3 – 2i)² ||

A: Given that: (a)4+3i-1-3i(b)(1+i)(3-4i)(4-i)(c)i(2+2i)3(3-2i)2   NOTE: As per our answering…

Q: -4+8i/-9+3i

A: Given: -4+8i-9+3i To find: The simplified form of the given equation.

Q: Add / subtract: A) (-1+ 2i) + (-2 + 5i) B) (2-3i) - (-2+ 3i)

A:

Q: (8 – 3i)(-7 – 6i)

A:

Q: Simplify: 5 – 5i - 2i

A:

Q: If a = 2x -5i and b: 5x, then find the value of ab in fully simplified form.

A: Given,          a=2x-5i and b=5x

Q: Simplify: -3i(4 + 2i)

A:

Q: Simplify (6 - 3i) + [(4 - 2i) - (3 + i)].

A:

Q: Simplify. (-2+4i)(- 3 + 2i)

A:

Q: Simplify (2 – 3i)²

A:

Q: Simplify: - 3i 1+ 3i

A:

Q: (-4+i)-(5-7i)² Simplify 3i

A: We use i2=-1

Q: (-5 + 3i) (-3 +6i)

A: To simplify the given expression.

Q: separate into real and imaginary (2+√5i÷3−√2i)-2

A: Given Expression :

Q: perform the indicated operation and simplify. (-2 - 3i)(4 - 8i)

A: Given expression is -2-3i4-8i.

Q: If (x + yiX3 - 2i)= 16 - 2i, find the value of y

A: To find the value of y we compare both side  imaginary parts

Q: do Subtrect 7-6i-19-9:)

A:

Q: write in standard form: (3-4i)(2+i)

A: From the given information, (3-4i)(2+i) is the multiplication of two complex numbers.

Q: Evaluate (2i)2 - √-4 + √-7i

A:

Q: Divide. 3+7i 1+ i

A: Given: 3+7i1+i We know that; a+ibc+id=ac-bd+ad+bci

Q: Divide. -5i -3-2i Write your answer as a complex number in standard form.

A: The given expression is -5i-3-2i

Q: Multiply (3 - 2i)(4 + 3i)

A:

Q: (-1+i)-(-7+4i)-5

A: Simplify the expression (–1+i) – (–7+ 4i) – 5 as follows.(–1+ i) – (–7+ 4i) – 5 = –1+ i +7– 4 i – 5…

Q: Multiply. 9i – 9i • 2i

A: Given,          -9i·2i

Q: Divide (4 + 3i)/(2 - i) (A) 11+10i/5 B) 1+2i

A:

Q: Simplify: (4i)3

A: Distribute the cube

Q: Simplify: (3 + 2i) (4 - 5i)

A: (3+2i)(4-5i)

Q: Solve: (1+5i)^3. O 110 - 74j O -74 - 110j O 74 + 110j O 110 + 74j

A:

Q: Simplify the expression, (4-3i) (-3+6i) - (2-i). Show your work

A: topic - complex numbers

Q: What is the difference of (-3+2i) and (6+3i)?

A:

Q: Simplify: -5i 1– 4i |

A:

Q: 之= 1+4i

A: Given: z=2+4i We know that if z=a+ib then z is given by z=a2+b2…

Q: Simplify (3 + 7i)8

A:

Q: How do I multiply (2+3i)(4+6i) and what is the answer in its simplest form

A:

Q: . Simplify the expression, (4 – 3i)(-3+ 6i) – (2 – i). Show your work.

A:

Q: Write the complex conjugate of -4+4i in exponential form.

A: The complex number z=x+iy=reiθ where r=x2+y2,θ= tan-1yx

Q: Simplify (4+3i)(2i-5)

A: Here we use concept of complex Number i.e. i=√-1 or i2 = -1

Q: Evaluate (3i)(2i)

A: a)   From the given problem:   Z=(3i)(2i)   As we know that,  i2=-1.   So,   Z=(3i)(2i)=6i2=6-1=-6…

Q: Divide. 4. -3-2i Write your answer as a complex number in standard form.

A: Given that 4-3-2i. Simplify as follows.

Q: -6-3i/8i

A: The given complex expression (number) is: -6-3i8i  To simplify this, multiply the complex number i…

Q: 4) -3i(4i-5)

A:

Q: Simplify (7 + 3i) 2 [(2 + i) 2 (3 - 4i)].

A: Given, (7+3i)2(2+i)2(3-4i)

Q: a) (2+4i)*

A:

Q: Find the product of (10 – 2i) and its conjugate. product = -(10 – 2i)

A:

Q: Simplify. 4+5i 2.

A: Given,          24+5i

Q: b) Im 1-7i 2+5i,

A:

Q: -4i (6 – 3i)

A: The solution for the above question is as shown below.

Q: (7+3i)-(-4-15i)

A: