Question
Asked Dec 25, 2019
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Figure P22.59 shows the path of a beam of light through several
layers with different indices of refraction. (a) If Θ1 = 30.0°,
what is the angle Θ2 of the emerging beam? (b) What must

the incident angle Θ1 be to have total internal reflection at the
surface between the medium with n = 1.20 and the medium
with n = 1.00?

n= 1.60
n= 1.40
n = 1.20
Ө2
n = 1.00
Figure P22.59
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n= 1.60 n= 1.40 n = 1.20 Ө2 n = 1.00 Figure P22.59

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Expert Answer

Step 1
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Given, Refractive index n =1.6 п, 3D 1.4 n = 1.2 Ng =1

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Step 2
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Let the reflective angle of layer 1 is Oa and the incident angle of layer 2 is Oa. n = 1.60 n = 1.40 3 n = 1.20 n= 1.00 2.

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Step 3
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Snell's law for layer 1: п, sin @, 3Dn sin e, п, sin @ sin e, п, 1.4 sin 30° sin 0, 1.6 0, = 25.94°

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Science

Physics

Wave Optics