(n-2)! 2! = In-8)! 8! (n-2) (n-3) (n- 4)ln-5) (n.6) In-1)ln-e)! (n-P)! 8X7X6 x5 X4X3 (n2)In.3) In-4)n-5| In-61(n-1) : 8×7 x6 XJX4X3 = (10-a)l10-3) l10-4) li0-개10-6lo-기 3D h= l0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.6: Permutations
Problem 13E
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can u explain this part please, i dont get it

ラ
(n-2)! 2! =
In-8)! 8!
(h-1) (n-3)(n- 4) In-5) (n.6) (n-1n-l = M-P)! 8X7X6 X5X4X3
:(10-2)l10-3)|10-4)l10-5|0-6 )||0- 1)
ニ
h= 10
介
Transcribed Image Text:ラ (n-2)! 2! = In-8)! 8! (h-1) (n-3)(n- 4) In-5) (n.6) (n-1n-l = M-P)! 8X7X6 X5X4X3 :(10-2)l10-3)|10-4)l10-5|0-6 )||0- 1) ニ h= 10 介
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