n our 32-bit MIPS architecture, what is the minimum number of byte e allocated to store the following variable: nt my_array[11]; 12 D 44 O11 45
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Explain all options
![Question 66',
In our 32-bit MIPS architecture, what is the minimum number of bytes that need to
be allocated to store the following variable:
int my_array[11];
12
44
11
4
45](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2fad787b-59bc-4d01-b4a7-f4069809e760%2F03b1d3b6-b81e-4b9e-b0c1-575844bf2ca9%2F21o9sz5_processed.png&w=3840&q=75)
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- This question is on Computer Architecture. Translate the following arithmetic and logical expressions written in C programming language intoinstructions sequences written in MIPS Assembly language. You may assume that the values (orbase addresses) of the variables a, b, c, and d are in the general-purpose registers $s0, $s1,$s2, and $s3. 1. d[3] = a - b + c[7];2. c[5] = (a << 3) & (b >> 2);Here, <<, >>, and & indicate the bitwise left-shift, right-shift, and AND operations respectively.Write a service routine which resets all elements of an array that resides in memory location from A000 H to A0FF H with DS equal to 0000 H. The service routine address is CS:IP where CS is 2000 H and IP is 0100H. Assume the interrupt type that is called is 50 (x8086- nano)Suppose we have a byte-addressable computer using direct mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 16 bytes. a. Determine the number of bits of the offset field. b. Determine the number of bits of the block (or slot) field. c. Determine the number of bits of the tag field. d. To which cache block would the hexadecimal address 0x2468 map? e. What is the tag of the hexadecimal address 0x2468 f.To which cache block would the hexadecimal address 0x864A map? g. What is the tag of the hexadecimal address 0x864A?
- Show how the following values would be stored by byteaddressable machines with 32-bit words, using little endian and then big endian format. Assume that each value starts at address 10 . Draw a diagram of memory for each, placing the appropriate values in the correct (and labeled) memory locations.Q.) 0x14148888Suppose we have a byte-addressable computer using direct mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 8 bytes. a. Determine the number of bits of the tag field. b. To which cache block would the hexadecimal address 0x2468 map? c. What is the tag of the hexadecimal address 0x2468A computer is using a fully associative cache and has 216 bytes of main memory (byte addressable) and a cache of 64 blocks, where each block contains 32 bytes. a. How many blocks of main memory are there? b. What will be the sizes of the tag, index, and byte offset fields? c. To which cache set will the memory address 0xF8C9(hexadecimal) map?
- What are the benefits of segmented memory address translation over a straight translation?Suppose a computer using direct-mapped cache has 232 (that's 232)232) bytes of byte-addressable main memory, and a cache size of 512 bytes, and each cache block contains 64 bytes. How many blocks of main memory are there? What is the format of a memory address as seen by cache, i.e. what are the sizes of the tag, block, and offset fields? To which cache block will the memory address 0x13A4498A map?You are given a main memory of 64Mbytes with each byte addressable and asked to design a cache memory using direct mapping. The main memory is organized as blocks of 8bytes. The cache memory must have a size of 512Kbytes. What should be the size of the tag in bits?
- Suppose a computer using direct mapped cache has 4M byte of byte-addressable main memory, and a cache of 512 blocks, where each cache block contains 64 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag, block, and offset fields? c) To which cache block will the memory address 0x00007266 map?Suppose a computer using fully associative cache has 4G bytes of byte-addressable main memory and a cache of 512 blocks, where each cache block contains 128 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag and offset fields? c) To which cache block will the memory address 0x018072 map?Fill in blank Suppose that linear page table is used where the memory addresses are 12-bit binary numbers and the page size is 256 bytes. If a virtual address in binary format is 101000011100, then the VPN (virtual page number) in binary format will be ---------