Naturally found uranium consists of 99.274% 238U, 0.720% 235U, and 0.006% 233U. As we have seen, 235U is the isotope that can undergo a nuclear chain reaction. Most of the 235U used in the first atomic bomb was obtained by gaseous diffusion of uranium hexafluoride, UF6(g).  (a) What is the mass of UF6 in a 30.0-L vessel of UF6 at a pressure of 695 torr at 350 K?  (b) What is the mass of 235U in the sample described in part (a)?  (c) Now suppose that the UF6 is diffused through a porous barrier and that the change in the ratio of 238U and 235U in the diffused gas can be described by Equation 10.23 (shown in the attached picture). What is the mass of 235U in a sample of the diffused gas analogous to that in part (a)?  (d) After one more cycle of gaseous diffusion, what is the percentage of 235UF6 in the sample?

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Chapter9: Gases
Section: Chapter Questions
Problem 86E: During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6...
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Naturally found uranium consists of 99.274% 238U, 0.720% 235U, and 0.006% 233U. As we have seen, 235U is the isotope that can undergo a nuclear chain reaction. Most of the 235U used in the first atomic bomb was obtained by gaseous diffusion of uranium hexafluoride, UF6(g). 

(a) What is the mass of UF6 in a 30.0-L vessel of UF6 at a pressure of 695 torr at 350 K? 

(b) What is the mass of 235U in the sample described in part (a)? 

(c) Now suppose that the UF6 is diffused through a porous barrier and that the change in the ratio of 238U and 235U in the diffused gas can be described by Equation 10.23 (shown in the attached picture). What is the mass of 235U in a sample of the diffused gas analogous to that in part (a)? 

(d) After one more cycle of gaseous diffusion, what is the percentage of 235UF6 in the sample?

Now suppose that the UF6 is diffused through a porous barrier and that the change in the ratio of 238 U
and 235 U in the diffused gas can be described by the equation
3RT/M1
3RT/M2
What is the mass of 235 U in a sample of the diffused gas
M2
M1
%3D
%3D
T2
Urms2
analogous to that in part A?
AZ
?
mass of 246 U =
Transcribed Image Text:Now suppose that the UF6 is diffused through a porous barrier and that the change in the ratio of 238 U and 235 U in the diffused gas can be described by the equation 3RT/M1 3RT/M2 What is the mass of 235 U in a sample of the diffused gas M2 M1 %3D %3D T2 Urms2 analogous to that in part A? AZ ? mass of 246 U =
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