Flux and nonconducting shells. A charged particle is suspended at the center of two concentric spherical shells that are very thin andmade of nonconducting material. Figure (a) shows a cross section. Figure (b) gives the net flux through a Gaussian sphere centeredon the particle, as a function of the radius r of the sphere. The scale of the vertical axis is set by ,- 3.0x 105 N-m²/C. (a) What is thecharge of the central particle? What are the net charges of (b) shell A and (c) shell B?(a) Number 1.06(b) Number(c) Number-3.19E125.31E12(4)Units μCUnitsⒸ(10²° N+m²/C)UCUnits PC(())

Answered: Image /qna-images/answer/5177cea8-a2de-446c-9492-6aedf56aa187.jpg

nconducting material. Figure (a) shows a cross section. Figure (b) gives the net flux through a Gaussian sphere centered cle, as a function of the radius r of the sphere. The scale of the vertical axis is set by @,- 3.0x 105 N-m²/C. (a) What is the he central particle? What are the net charges of (b) shell A and (c) shell B? 1.06 -3.19E12 5.31E12 3) Units pC (10²° N+m²/C) Units UC Units PC 4₁ (6)

nconducting material. Figure (a) shows a cross section. Figure (b) gives the net flux through a Gaussian sphere centered cle, as a function of the radius r of the sphere. The scale of the vertical axis is set by @,- 3.0x 105 N-m²/C. (a) What is the he central particle? What are the net charges of (b) shell A and (c) shell B? 1.06 -3.19E12 5.31E12 3) Units pC (10²° N+m²/C) Units UC Units PC 4₁ (6)

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 71P: A solid cylindrical conductor of radius a is surrounded by a concentric cylindrical shell of inner...

See similar textbooks

Similar questions

A particle with charge Q is located a small distance immediately above the center of the flat face of a hemisphere of radius R as shown in Figure P19.38. What is the electric flux (a) through the curved surface and (b) through the flat face as 0?
What is the area of the square sheet if an electric flux of is passing thru it, with an electric field of and creating an angle of 30° from the surface area of the square sheet? From the problem, which of the following is the correct variable for the required? Group of answer choices A E Φ φ
An electric field given by = 4.8 - 2.7(y2 + 7.5) pierces the Gaussian cube of edge length 0.460 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube?
An electric field given by E = 5x i - 7y j pierces through a cubic Gaussian surface of edge length 2.0 m and positioned as shown in the figure ( E is in N/C and the position x, y are in meters). Calculate the electric flux of through the top face ( in N.m2/C)
A cylinder of diameter 1.72 m is in a region where the electric field is as shown in the figure below. If E1 = 38.0 N/C and E2 = 20.1 N/C, what is the net flux through the two end faces of the cylinder? Note that the diagram is not to scale. N · m2/C
A uniformly charged wire produces an electric field E = (5.60 N/(C · m2))r2r̂. Consider a closed cylinder with the charged wire centered inside it and situated along the axis of the cylinder. What is the net flux through the closed cylinder if the diameter of the cylinder is 0.750 m and the length of the cylinder is 2.40 m? N · m2/C
Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: The flux through surface 1 is: . The flux through surface 2 is: . The flux through surface 3 is: . The flux through the surface on the xy plane is: . The flux through the surface on the xz plane is: . The flux through the surface on the yz plane is: . Taking the algebraic sum, the net electric flux through the cube is: .
A large non-conducting slab of area A and thickness d has a charge density rho=Cx^4. The origin is through the center of the slab. That is to say, it bisects the slab into two equal volumes of d/2 thickness and with an area of A, with -d/2 to the left of x=0, and d/2 to the right of x=0. Express all answers in terms of C, x, and any known constants. Gaussian surface 1 (cylinder) is located such that its volume encompasses the charge contained within the slab. Apply Gauss's Law to cylinder 1 to determine the electric field to the left and to the right of the slab. Make sure you incude the domains over which the field is valid.
The rectangular surface in the figure below is in a uniform electricfield region with strength of 45.4 N/C. If the surface has a dimensionof 5.00 m × 9.00 m, and the electric flux through the surface is 1040N · m2/C^2, the angle is?
Solve the following:a. Find the flux through a spherical Gaussian surface of radius a= 1 m surrounding a charge of 8.85 pC.b. Find the value of the electric field at a distance r= 10 cm fromthe center of a non-conducting sphere of radius R= 1 cm whichhas an extra positive charge equal to 7 C uniformly distributedwithin the volume of the sphere.
A cylinder of diameter 1.72 m is in a region where the electric field is as shown in the figure below. If E1 = 42.4 N/C and E2 = 23.1 N/C, what is the net flux through the two end faces of the cylinder? Note that the diagram is not to scale.
A square that has 23 cm long edges is centered on the x axis in a region where there exists a uniform electric field given by E= (2.1 kN/C). 1) What is the electric flux of this electric field through the surface of a square if the normal to the surface is in the +x direction? in N · m2/C 2) What is the electric flux through the same square surface if the normal to the surface makes a 62° angle with the y axis and an angle of 90° with the z axis? in N · m2/C