Please help me and exlain so I can understand! Near room temperature, the density of ethanol can be expressedusing the equation3D(-8,99 ×10 g mi K^)T+ (1.051 g mL')where d is the density in units of g mL1 Tis the temperature in units ofKevinDetermine the temperature (in units of Kelvin) at which the density ofethanol will be 0.813 g mL 1. Express your result with the appropriatenumber of significant figures and correct units, assuming that thenumerical values in the equation are not exact.

Given the relation between density (d) and Temperature (T): d = (-8.99 × 10-4 g ml-1 K-1)T + (1.051…

Near room temperature, the density of ethanol can be expressed using the equation 3(-8,99 × 107g m K^)T+ (1.051 g mL*) where dis the density in units of g mL1 Tis the temperature in units of evin. Determine the temperature (in units of Kelvin) at which the density of ethanol will be 0.813 g mL 1. Express your result with the appropriate number of significant figures and correct units, assuming that the numerical values in the equation are not exact.

Near room temperature, the density of ethanol can be expressed using the equation 3(-8,99 × 107g m K^)T+ (1.051 g mL*) where dis the density in units of g mL1 Tis the temperature in units of evin. Determine the temperature (in units of Kelvin) at which the density of ethanol will be 0.813 g mL 1. Express your result with the appropriate number of significant figures and correct units, assuming that the numerical values in the equation are not exact.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.17QAP

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