I need answers for both Problem 4|.For each part of the below question, choose one correct answer from the drop-down multiple choice menu box.An object is located at a distance s, = 5 cm in front of a mirror having a focal length f = -3 cma) |What is the type of the miror?The mirror isb)Find the position of the image sic)Find the radius of curvature R.R=d)IAssume s, = -4.7 cm. Find the transverse magnification MT.MT =е).Using the result from part d), is the image upright or inverted?The image isUprightInvertedNext pageJump to. For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS).A thin biconvex lens made of heavy flint glass (n= 1.89) has a focal length in air of 60 cm. The radius of curvature of the first surface is twice the second surface's radius.a)| What is the sign of the radius of the first surface?Choose one;OpositiveOnegativeb)iWhat is the sign of the radius of the second surface?Choose one:OpositiveOnegativec)Calculate the radius of curvature of the first surface R.R1 =cmd) I-If R1 = 208. 3 cm, R2 = 104.1 cm, n = 1.89, calculate the new focal length in air of this lens, fnew.fnew =If the lens is now immersed in a medium that has an index of refraction of 1.575, calculate the focal length in the medium fmedium (use R, = 208. 3 cm, R2 = 104. 1e) [cm and n = 1.89).fmediumcm

Answered: Image /qna-images/answer/ad90c1fa-29d5-4a68-87a3-3806f05352e6.jpg

Answered: need answers for both

Science

Physics

need answers for both

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter9: Optics

Section: Chapter Questions

Problem 17P: . If the mirror described in the previous problem is used to form an image of the same object now...

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Question

I need answers for both

For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS).
A thin biconvex lens made of heavy flint glass (n= 1.89) has a focal length in air of 60 cm. The radius of curvature of the first surface is twice the second surface's radius.
a)
| What is the sign of the radius of the first surface?
Choose one;
Opositive
Onegative
b)i
What is the sign of the radius of the second surface?
Choose one:
Opositive
Onegative
c)
Calculate the radius of curvature of the first surface R.
R1 =
cm
d) I-
If R1 = 208. 3 cm, R2 = 104.1 cm, n = 1.89, calculate the new focal length in air of this lens, fnew.
fnew =
If the lens is now immersed in a medium that has an index of refraction of 1.575, calculate the focal length in the medium fmedium (use R, = 208. 3 cm, R2 = 104. 1
e) [
cm and n = 1.89).
fmedium
cm

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