Need some help with this c++ recursive function: Write the function int countEights(int n). Inside the function, compute recursively (no loops) the count of the occurrences of 8 as a digit inside the parameter n. Except that an 8 with another 8 immediately to its left counts double, so 8818 yields 4. Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12). Here are some examples: countEights(8) returns 1 countEights(818 returns 2 countEights(8818) returns 4

Need some help with this c++ recursive function: Write the function int countEights(int n). Inside the function, compute recursively (no loops) the count of the occurrences of 8 as a digit inside the parameter n. Except that an 8 with another 8 immediately to its left counts double, so 8818 yields 4. Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12). Here are some examples: countEights(8) returns 1 countEights(818 returns 2 countEights(8818) returns 4

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 8SA

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Need some help with this c++ problem In order to compute a power of two, you can take the next-lower power and double it. For example, if you want to compute 211 and you know that 210 = 1024, then 211 = 2 × 1024 = 2048. Based on this observation, write a recursive function int pow2(int n) where n is the exponent. If the exponent is negative, return -1. int pow2(int n) { ..... }
Below,enter code to complete implementation of a recursive function sum_all_integers(), which takes an input n and adds all intergers preceding it, up to n: add_all_integers(n):
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