New Authors Established Authors Total Successful 9. 24 33 Unsuccessful 12 59 71 Total 21 83 104 What percentage of new authors are unsuccessful? (Give the answer to two decimal places.) % What percentage of unsuccessful authors are new? (Give the answer to two decimal places.)
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- A veterinary nutritionist developed a diet for overweight dogs. The total volume of food consumed remains the same, but one-half of the dog food is replaced with a low-calorie “filler” such as canned green beans. Six overweight dogs were randomly selected from her practice and were put on this program. Their initial weights were recorded, and they were weighed again after 4 weeks. The results of the experiment are shown below. At α=0.05, can it be concluded that the dogs significantly lost weight?A new purification unit is installed in a chemical process. Before its installation, a random sample yielded the following data about the percentage of impurity: x1 = 9.85 , S12 = 81.73 , and n1 = 8 . After installation, a random sample resulted in x2 = 8.08 , S2 = 78.46 , and n2 = 10 .A hospital administrator claims that the proportion of knee surgeries that are successful is 87%. To test this claim, a random sample of 450 patients who underwent knee surgery is taken and it is determined that 371 of these patients had a successful knee surgery operation. The following is the setup for this hypothesis test: H0:p = 0.87 Ha:p ≠ 0.87 Find the p-value for this hypothesis test for a proportion and round your answer to 3 decimal places. The following table can be utilized which provides areas under the Standard Normal Curve: z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -2.9 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.001 0.001 0.001 -2.8 0.003 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002 -2.7 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 -2.6 0.005 0.005 0.004 0.004 0.004 0.004 0.004 0.004 0.004 0.004 -2.5 0.006 0.006 0.006 0.006 0.006 0.005 0.005 0.005 0.005 0.005
- Tests for adverse reactions to a new drug yielded the results given in the table. At a 0.05 level of significance, test the claim that the treatment (drug or placebo) is independent of the reaction (whether or not headaches were experienced). (16) Drug Placebo Headaches 11 7 No Headaches 73 91A vending machine company wants to check three of its machines to determine if they are properly dispensing 12 ounces of coffee. Test by using α=0.05. Their data is given below. Machine A Machine B Machine C 11.8 11.7 12.2 12.1 11.9 12.1 12.0 11.7 12.0 11.9 11.8 11.9 12.1 12.0 12.2 Group of answer choices There is sufficient evidence to reject the claim that the proportions are equal because the p-value 0.0255 < 0.05 There is insufficient evidence to conclude the claim that the proportions are equal because the p-value 0.0255 < 0.05 There is insufficient evidence to reject the claim that the proportions are equal because the p-value 0.0255 < 0.05 There is sufficient evidence to conclude the claim that the proportions are equal because the p-value 0.0255 < 0.05P2. A company that produces a certain medicine claims that less than 0.1% of the people who take the medicine will suffer major side effects. The company says that this claim is based on a sample of a 1000-person survey. Based on a 99% confidence, determine the number of independent “test” people needed to detect a change of 10% in the claimed ratio of 0.1% of the people affected by major side-effects.
- A population of trees has a mean leaf length of 6.2 inches. A sample of 17 of these trees in a particular neighborhood has a mean length of 3.2 inches. If SS = 144 for this sample, what is Cohen's d for this example, and what is the strength of the treatment effect, which in this case is growing in a particular neighborhood?Consider a sample of n = 114 women drawn randomly from the membership list of the National Organization for Women (N.O.W.), x = 24 of whom were found to smoke. Use the result of this sample to test whether the rate found is significantly different from the United States proportion of 0.31 for women and provide the z-statistic value below.A sample of 12 male and 12 female students were surveyed and the amount spent on food last week were recorded. The results are summarized in the table below. Test for the hypothesis that the weekly amount spent on food of male and female students is the same, at a=0.10. Male Female 623 685 537 629 613 517 588 580 651 658 688 582 526 614 579 528 814 655 878 804 660 549 722 617 a. What are the null and alternative hypotheses?b. What is the critical value? (4 decimal points)c. What is the test statistic? (4 decimal points)e. Reject or accept null hypothesis?
- From previous studies, it is concluded that 60% of phone numbers in a certain city are unlisted. A researcher claims that the proportion is smaller than 60% and decides to survey 600 working adults. Test the researcher's claim at the α=0.025 significance level. Preliminary: Is it safe to assume that n≤0.05 of all subjects in the population? Yes No Verify np(1−p)≥10. Round your answer to one decimal place.np(1−p)= Test the claim: H0:μ=0.6Ha:μ≠0.6 H0:μ≥0.6Ha:μ<0.6 H0:p≥0.6Ha:p<0.6 H0:μ≤0.6Ha:μ>0.6 H0:p=0.6Ha:p≠0.6 H0:p≤0.6Ha:p>0.6The null and alternative hypotheses are The test isIn manufacturing processes, it is of interest to know with confidence the proportion of defective parts. Suppose that we want to be reasonably certain that less than 4 % of a company's widgets are defective. To test this, we obtain a random sample of 250 widgets from a large batch. Each of the 250 widgets is tested for defects, and 6 are determined to be defective,based upon the manufacturers standards.using a= 0.01, is this evidence that less than 4% of the company's widgets are defective? State the hypothesis, list and check the conditions, calculate the test statistic, find the p-value, and make a conclusion in a complete sentence related to the scenario.The following table shows the results of a screening test hypothesized to identify persons at risk for a rare blood disease. Compute the False Positive Fraction of the test. No Disease Disease Screen Negative 1351 20 Screen Positive 39 41