New nodes are added to the. . of the stack O a. Front O b. Back O c. Bottom O d. top
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- Clarify the back stack's relationship with the back button.A skip listThe second programming homework is already on a server (http://marmoset.famnit.upr.si).In this task, a skip list data structure should be implemented. You can follow the followinginstructions:- Implement the class NodeSkipList with two components, namely key node and arrayof successors. You can also add a constructor, but you do not need to add anymethod.- In the class SkipList implement a constructor SkipList(long maxNodes). The parameter maxNodes determines the maximal number of nodes that can be added to askip list. Using this parameter we can determine the maximal height of a node, thatis, the maximal length of the array of successors. As the maximal height of a nodeit is usually taken the logarithm of the parameter. Further, it is useful to constructboth sentinels of maximal height.- In the class SkipList it is useful to write a method which simulates coin flip andreturns the number of all tosses until the first head comes up. This number representsthe height of a node…Given the following code, how would you make it thread-safe? // basic node structuretypedef struct __node_t { int key; struct __node_t *next;} node_t; // basic list structure (one used per list)typedef struct __list_t { node_t *head; } list_t; void List_Init(list_t *L) { L->head = NULL; } int List_Insert(list_t *L, int key) { node_t *new = malloc(sizeof(node_t)); if (new == NULL) { perror("malloc"); return -1; // fail } new->key = key; new->next = L->head; L->head = new; return 0; // success } int List_Lookup(list_t *L, int key) { node_t *curr = L->head; while (curr) { if (curr->key == key) { return 0; // success } curr = curr->next; } } Group of answer choices A. list_t is already thread-safe and does not need any locks in any of its operations. B. Add a lock to the list_t struct, initialize the lock in the List_Init, and then any operation that involves a…
- Please use Java Write a method “removeBottomItemStack” that takes a stack of integers and removes the first item added (the one at the bottom).Using the generic stack psuedocode below, what was the last value popped?Push 9Pop xPush 7Push 6Push 5Pop xPush 3Pop xPop x 5 3 7 6Which best describes this axiom: ( List ( ) ) . getLength ( ) = 0 None of these You cannot get the length of a newly created list A newly created list has a length A newly created list has a length of zero
- The calculator works as follows: if number, push to a stack if operator, pop two numbers, operate on them, and push the result if I hit an operator and there are not two numbers on the stack, it's a bad expression if I get to the end of the expression and there is not exactly one number on the stack, it's a bad expression. YOUR IMPLEMENTATION, 30 points: 10 - the input to output happening without a crash 10 for implementing LinkedListBasedStack 10 for implementing ArrayList YOUR CALCULATOR ONLY NEEDS TO WORK FOR +, -, and * YOUR CALCULATOR ONLY NEEDS TO WORK ON INTEGERS. RPNStringTokenizer.java package template; import java.util.ArrayList; public interface RPNStringTokenizer { public static ArrayList<String> tokenize (String expression) { // take a string. If it is valid RPN stuff - integers or operators // - then put them in a list for processing. // anything bad (not int or one of the operators we like) and return a null. // YOU WRITE THIS! return null; } }…Start this lab with the code listed below. The LinkedList class defines the rudiments of the code needed to build a linked list of Nodes. Complete the code for the removeFirst method, which should remove and return the first element in the linked list. Throw a NoSuchElementException if the method is invoked on an empty list. Use the LinkedListRunner class’s main method to test your code. import java.util.NoSuchElementException;public class LinkedList{ private Node first; public LinkedList() { first = null; } public Object getFirst() { if (first == null) { throw new NoSuchElementException(); } return first.data; } public void addFirst(Object element) { Node aNode = new Node(); aNode.data = element; aNode.next = first; first = aNode; } public Object removeFirst() { // put your code here } public String toString() { String temp = ""; Node current = first; while (current != null) { temp =…I need to add an item to a linked list using a method. its an object consisting of a name, int, double, double, int. public static Person addPerson (Person head, Person toAdd, int position) { }
- My code does not produce the required output, can anyone let me know what seems to be off? Input: from Node import Node from LinkedList import LinkedList def print_linkedlist(list): print(f'Linked List ------ Nodes ----------------------------------') print(f'head: {list.head.name:<6}', end=' ') node = list.head while node != None: print(f"{node.name:<12}", end=' ') node = node.next print() print(f'tail: {list.tail.name:<6}', end=' ') node = list.head while node != None: print(f"data:{node.data:<7}", end=' ') node = node.next print() print(f' ', end=' ') node = list.head while node != None: if node.next != None: print(f"next:{node.next.name:<7}", end=' ') else: print("next:None") node = node.next print() print(f' ', end=' ') node = list.tail while node != None: if node.prev != None:…My code does not produce the required output, can anyone let me know what seems to be off? Input: from Node import Node from LinkedList import LinkedList def print_linkedlist(list): print(f'Linked List ------ Nodes ----------------------------------') print(f'head: {list.head.name:<6}', end=' ') node = list.head while node != None: print(f"{node.name:<12}", end=' ') node = node.next print() print(f'tail: {list.tail.name:<6}', end=' ') node = list.head while node != None: print(f"data:{node.data:<7}", end=' ') node = node.next print() print(f' ', end=' ') node = list.head while node != None: if node.next != None: print(f"next:{node.next.name:<7}", end=' ') else: print("next:None") node = node.next print() print(f' ', end=' ') node = list.tail while node != None: if node.prev != None:…I have a large number of string objects whose order is not really important, but I'd like to remove all duplicates. What container should I use to store them? Pick ONE option A dynamic array A linked list A set A map A Queue