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Newton's Law of Cooling states that the temperature (T) of an object at any time (1), in minutes, can be described by the equation T= Tg * (To - Tg)e*, where Tg is the temperature of he surrounding environment, Tg is the initial temperature of the object, and k is the cooling rate. What is the cooling rate of an object if the inital temperature was 400* C, the surrounding environment temperature was 30* C, and it took 105 minutes to cool down to 125° C. Round your result to 3 decimal places. Ok=0.011 Ok=0.012 OK=0.013 Ok=0.014

Newton's Law of Cooling states that the temperature (T) of an object at any time (1), in minutes, can be described by the equation T= Tg * (To - Tg)e*, where Tg is the temperature of he surrounding environment, Tg is the initial temperature of the object, and k is the cooling rate. What is the cooling rate of an object if the inital temperature was 400* C, the surrounding environment temperature was 30* C, and it took 105 minutes to cool down to 125° C. Round your result to 3 decimal places. Ok=0.011 Ok=0.012 OK=0.013 Ok=0.014

College Algebra
College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...
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Newton's Law of Cooling states that the temperature (7) of an object at any time (1), in minutes, can be described by the equation T= Ts + (To - Ts)e*, where Ts is the temperature of the surrounding environment, To is the initial temperature of the object, and k is the cooling rate. What is the cooling rate of an object if the initial temperature was 400° C, the surrounding environment temperature was 30° C, and it took 105 minutes to cool down to 125° C. Round your result to 3 decimal places. k = 0.011 Ok= 0.012 Ok= 0.013 Ok=0.014
Transcribed Image Text:Newton's Law of Cooling states that the temperature (7) of an object at any time (1), in minutes, can be described by the equation T= Ts + (To - Ts)e*, where Ts is the temperature of the surrounding environment, To is the initial temperature of the object, and k is the cooling rate. What is the cooling rate of an object if the initial temperature was 400° C, the surrounding environment temperature was 30° C, and it took 105 minutes to cool down to 125° C. Round your result to 3 decimal places. k = 0.011 Ok= 0.012 Ok= 0.013 Ok=0.014
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