nn MEGMar(1-|-.0) i=1 j=1 i=1 j=1 = GĞMar(1-r- al.0) + GÖMar(1–|h- 2|,0) + ciğMar(1- |21 -23,0) + cĞMar(1–- |12 – 1|,0) + c»©»Mar(1– |22 – 2| ,0) + c¢Mar(1– |22 – 23|,0) + c3¢jMar(1– |r3 – 1|,0) + c3&Mar(1– |r3 – 2| ,0) + C3čMar(1–|23 – 23| ,0) Now we take common factors (la+ lel* + lesf)Mar(1,0) + (c +cG)Mar(1– |2, – 12|,0) + (c+ c3ti)Max(1– |r) – 13|,0) + (cEs + Cz&»)Mar(1– |r2 – r3|,0) let x = 1, x2 = X3 = 0 we get = ((aľ + l>f + les)Mar(1,0) + (ci2 + 26)Mar(1,0) + (Ges+ cG)Mar(1,0) + (2s + c36z)Max(1,0) Since Max(1,0) = 1 (lel + lof +lsf) + (+5) assume c = i, c2 = 0, c3 = 0 = (7 +0+0) +(0+0) + (0+0) +(0+0)
nn MEGMar(1-|-.0) i=1 j=1 i=1 j=1 = GĞMar(1-r- al.0) + GÖMar(1–|h- 2|,0) + ciğMar(1- |21 -23,0) + cĞMar(1–- |12 – 1|,0) + c»©»Mar(1– |22 – 2| ,0) + c¢Mar(1– |22 – 23|,0) + c3¢jMar(1– |r3 – 1|,0) + c3&Mar(1– |r3 – 2| ,0) + C3čMar(1–|23 – 23| ,0) Now we take common factors (la+ lel* + lesf)Mar(1,0) + (c +cG)Mar(1– |2, – 12|,0) + (c+ c3ti)Max(1– |r) – 13|,0) + (cEs + Cz&»)Mar(1– |r2 – r3|,0) let x = 1, x2 = X3 = 0 we get = ((aľ + l>f + les)Mar(1,0) + (ci2 + 26)Mar(1,0) + (Ges+ cG)Mar(1,0) + (2s + c36z)Max(1,0) Since Max(1,0) = 1 (lel + lof +lsf) + (+5) assume c = i, c2 = 0, c3 = 0 = (7 +0+0) +(0+0) + (0+0) +(0+0)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 64E
Related questions
Question
Look for c1 c2 and c3 complex number will give answer less than zero
![61%
3 3
nn
MaGpa - 1,)20 = EE Mar(1– |r.- r.0)
i=1 j=1
i=1 j=1
= GĞMar(1–|21-l.0)
+ GOMar(1 – |h- 2l0)
+ c&Mar(1- |21 - 23|,0)
+ GĞMar(1–|#2 – 21|.0).
+ c3»Mar(1–|22 – 22|,0)
+ cs&Mar(1– |22 – 23.0)
+ c3¢Mar(1–|23 – 21| .0)
+ Cz&,Mar(1– |rs – 2| ,0)
+ C3¢zMax(1–|23 – 23|,0)
Now we take common factors
(la + le2° + \es)Maz(1.0)
+ (ci + c»&)Max(1- |2, – r|,0)
+ (ci + c3ci)Max(1– |21 – 13|,0)
+ (c3 + cz&s)Maz(1– |r2 – 23|,0)
let x1 = 1, x2= X3 = 0 we get
(laľ + le°* + ]esl*)Max(1,0)
+ (cio + 2a)Mar(1,0)
+ (G t gá)Mar(1,0)
+ (o+g0)Mar(1,0)
Since Max(1, 0) = 1
%3D
assume e= i, c2= 0, C3 = (0
(* +0 + 0)
+ (0+0)
+(0+0)
+(0+0)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6080a182-9c27-4f69-8a23-b863d30485d5%2F7468c159-f43c-4311-9a3a-aa277cf5e397%2F6kv2du_processed.jpeg&w=3840&q=75)
Transcribed Image Text:61%
3 3
nn
MaGpa - 1,)20 = EE Mar(1– |r.- r.0)
i=1 j=1
i=1 j=1
= GĞMar(1–|21-l.0)
+ GOMar(1 – |h- 2l0)
+ c&Mar(1- |21 - 23|,0)
+ GĞMar(1–|#2 – 21|.0).
+ c3»Mar(1–|22 – 22|,0)
+ cs&Mar(1– |22 – 23.0)
+ c3¢Mar(1–|23 – 21| .0)
+ Cz&,Mar(1– |rs – 2| ,0)
+ C3¢zMax(1–|23 – 23|,0)
Now we take common factors
(la + le2° + \es)Maz(1.0)
+ (ci + c»&)Max(1- |2, – r|,0)
+ (ci + c3ci)Max(1– |21 – 13|,0)
+ (c3 + cz&s)Maz(1– |r2 – 23|,0)
let x1 = 1, x2= X3 = 0 we get
(laľ + le°* + ]esl*)Max(1,0)
+ (cio + 2a)Mar(1,0)
+ (G t gá)Mar(1,0)
+ (o+g0)Mar(1,0)
Since Max(1, 0) = 1
%3D
assume e= i, c2= 0, C3 = (0
(* +0 + 0)
+ (0+0)
+(0+0)
+(0+0)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra for College Students
Algebra
ISBN:
9781285195780
Author:
Jerome E. Kaufmann, Karen L. Schwitters
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra for College Students
Algebra
ISBN:
9781285195780
Author:
Jerome E. Kaufmann, Karen L. Schwitters
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning