Now that we know how to introduce the "-R" term into our matrix and we know how to find determinants, we can now convert our matrix into a Characteristic Equation similar to what we did back in unit 2. Given a matrix that has the "- R" term, its determinant becomes A -R det B = (A –R) (D-R) - CB C D -R Given the matrix 8. 3 -4 Introduce the "- R" term to the diagonal of the matrix then find the quadratic that makes up its determinant (aka: characteristic equation). A R2 - 6R - 28 B R2 - 6R – 4 R2 + 8R + 4 D) R2 - 10R + 28 E) R2 - 6R 16

Now that we know how to introduce the "-R" term into our matrix and we know how to find determinants, we can now convert our matrix into a Characteristic Equation similar to what we did back in unit 2. Given a matrix that has the "- R" term, its determinant becomes A -R det B = (A –R) (D-R) - CB C D -R Given the matrix 8. 3 -4 Introduce the "- R" term to the diagonal of the matrix then find the quadratic that makes up its determinant (aka: characteristic equation). A R2 - 6R - 28 B R2 - 6R – 4 R2 + 8R + 4 D) R2 - 10R + 28 E) R2 - 6R 16

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN:9781305071742

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter11: Matrices And Determinants

Section11.CR: Chapter Review

Problem 11CC

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