Now write the time domain function, assuming 60 Hz operation for the following rms phasors; repeat if these two expressions are peak phasors. Reminder that o = 2nf. (d) V= 200Z30° (e) V = 200
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- A circuit branch is found to have an equivalent impedance of Z=120−j45Ω. It is given that this impedance is a series combination of a 120Ω resistor and another passive component. If the circuit has a sinusoidal voltage source whose frequency is 120 Hz. What is the value of the component in series with the 120Ω resistor? (Note: Express the value assuming a metric scaling of μ(10-6). Provide your answer in decimal form, up to 3 decimal places.)The values of the parameters in the circuit shown are L1=8 mH; L2=2 mH; k=0.75; Rg=1 Ω; and RL=7 Ω. Ifvg=542 cos 1000t V, find 1. a) the rms magnitude of vo;2. b) the average power delivered to RL;3. c) the percentage of the average power generated by the idealvoltage source that is delivered to RL.Three branches having impedances of 3+j4 Ω, 16−j12 Ω, and−j4 Ω, respectively, are connected in parallel. What are the equivalent(a) admittance, (b) conductance, and (c) susceptance of the parallelconnection in millisiemens? (d) If the parallel branches are excited froma sinusoidal current source where i=8 cosωt A, what is the maximumamplitude of the current in the purely capacitive branch?
- Ex. 1844. Given a sinusoidal voltage source in series with R,L, and C. The sinusoidal voltage source has a frequency of 600 Hz. R=5 Ohms, L=2 milliHenry, C=4 microFarad, V=20sin(wt) volts. Solve for the capacitor steady-state phasor current and voltage. I(jw)=Aexp(jB), vc(jw)=Dexp(jE), IMPORTANT RESTRICTION: Express radian angles between [-pi/2,pi/2]. Solve for the capacitor steady-state time-domain current and voltage: i(t)=Fsin(wt+G), vc(t)=Hsin(wt+K) Ans: w,A,B,D,E,F,G,H,K all MKS units. ans:9A series circuit of RLC with following parameters, R=15 ohm, L=20 m H & C=100 micro Farad. VT=169.7 sin (337t-30) Volt. Find the following: Zt, , It, Voltage across each element, Power factor, apparent power, real or average power and reactive power and the total phasor diagram and power phasor diagramEx. 1844. Given a sinusoidal voltage source in series with R,L, and C. The sinusoidal voltage source has a frequency of 500 Hz. R=7 Ohms, L=8 milliHenry, C=6 microFarad, V=20sin(wt) volts. Solve for the capacitor steady-state phasor current and voltage. I(jw)=Aexp(jB), vc(jw)=Dexp(jE), Express radian angles between [-pi/2,pi/2]. Solve for the capacitor steady-state time-domain current and voltage: i(t)=Fsin(wt+G), vc(t)=Hsin(wt+K) Ans: w,A,B,D,E,F,G,H,K all MKS units. ans:9
- The following circuit is powered by a polyharmonic voltage whose expression is: v(t) = 100+141.sin (1000t) + 70.7.sin (2000t) V. It is requested: a) The expression of the instantaneous current.b) Plot the amplitude and phase spectra of the voltage and current.c) The values of the apparent, active, reactive and distortion powers, justifying the resultsIf y1=20 cos (ωt − 30°) and y2=40 cos (ωt + 60°), express y=y1 + y2 as asingle sinusoidal function.1. Solve by using trigonometric identities.2. Solve by using the phasor concept.five infinite-impedance volunteers,calibrated to read rms values,are connected as shown below. let R= 200, L=0.400H,C=6.0 Mf, and V=30.0 v. what's the reading of the voltmeter's V1,V2,V3,V4 and V5 if W= 200 rad/s
- The frequency of the sinusoidal voltage sourcein the circuit is adjusted until ig is in phase with vg.1. What is the value of ω in radians per second?2. If vg=15 cosωt V (where ω is the frequency found in [a]), what isthe steady-state expression for ig?1. For the following sinusoids, determine which one leads and by how much a. ?(?) = 10cos (4? − 60°) and ?(?) = 6sin (4? + 50°)b. ?ଵ(?) = 4cos (377? + 10°) and ?ଶ(?) = −20cos(377?)c. ?(?) = 13 cos(2?) + 5 sin(2?) and ?(?) = 15cos (2? − 11.8°)Help me please IN THE CIRCUIT SHOWN, THE VALUE OF THE CURRENT SOURCE IS IN RMS VALUE. DETERMINE: A) THE VOLTAGE (ONLY THE MAGNITUDE) AT THE INDUCTOR TERMINALS, VL B) THE VOLTAGE (ONLY THE MAGNITUDE) AT THE RESISTOR TERMINALS, VR C) THE AVERAGE POWER ABSORBED BY THE 40 Ω RESISTOR