nter the exact answer as an ordered triple, (x,y,z). Hint: There are multiple ways to solve this system of equations. A strategy is to eliminate one of the variables and end up with 2 equations in 2 variables. One way to do that is to begin with equation 2 to get z=14−2x−4y. Then substitute 14−2x−4y for z in equations 1 and 3. You now have 2 equations (the modified equations 1 and 3) in 2 variables (x and y).
nter the exact answer as an ordered triple, (x,y,z). Hint: There are multiple ways to solve this system of equations. A strategy is to eliminate one of the variables and end up with 2 equations in 2 variables. One way to do that is to begin with equation 2 to get z=14−2x−4y. Then substitute 14−2x−4y for z in equations 1 and 3. You now have 2 equations (the modified equations 1 and 3) in 2 variables (x and y).
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.7: Puzzle Problems
Problem 33P
Related questions
Question
9Solve the system of equations by any method.
(picture provided)
Enter the exact answer as an ordered triple, (x,y,z).
Hint: There are multiple ways to solve this system of equations.
- A strategy is to eliminate one of the variables and end up with 2 equations in 2 variables.
- One way to do that is to begin with equation 2 to get z=14−2x−4y.
- Then substitute 14−2x−4y for z in equations 1 and 3.
- You now have 2 equations (the modified equations 1 and 3) in 2 variables (x and y).
- Solve this smaller system for x and y and then use z=14−2x−4y to calculate z.
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