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Number of Credit Cards A bank vice president feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. Find the mean, variance, and standard deviation. Is the vice president correct? Number of cards X 1 4 Probability P(X) 0.03 0.44 0.27 0.08 0.18 O a. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is correct) mean = 1.94, variance = 1.356, standard deviation = 1.165 (Vice president is correct) mean = 1.94, variance = 1.356. standard deviation = 1.165 (Vice president is not correct) O d. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is not correct)

Number of Credit Cards A bank vice president feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. Find the mean, variance, and standard deviation. Is the vice president correct? Number of cards X 1 4 Probability P(X) 0.03 0.44 0.27 0.08 0.18 O a. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is correct) mean = 1.94, variance = 1.356, standard deviation = 1.165 (Vice president is correct) mean = 1.94, variance = 1.356. standard deviation = 1.165 (Vice president is not correct) O d. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is not correct)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Number of Credit Cards A bank vice president feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. Find the mean, variance, and standard deviation. Is the vice president correct? Number of cards X 1 3 4 Probability P(X) 0.03 0.44 0.27 0.08 0.18 O a. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is correct) b. mean = 1.94, variance = 1.356, standard deviation = 1.165 (Vice president is correct) O C. mean = 1.94, variance = 1.356, standard deviation = 1.165 (Vice president is not correct) O d. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is not correct)
Transcribed Image Text:Number of Credit Cards A bank vice president feels that each savings account customer has, on average, three credit cards. The following distribution represents the number of credit cards people own. Find the mean, variance, and standard deviation. Is the vice president correct? Number of cards X 1 3 4 Probability P(X) 0.03 0.44 0.27 0.08 0.18 O a. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is correct) b. mean = 1.94, variance = 1.356, standard deviation = 1.165 (Vice president is correct) O C. mean = 1.94, variance = 1.356, standard deviation = 1.165 (Vice president is not correct) O d. mean = 1.34, variance = 0.9244, standard deviation = 0.96 (Vice president is not correct)
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