O A binary tree has at most 1 child per node (it is binary: 0 or 1 children). O Recursion can be used to determine the number of nodes in a tree. O Recursion cannot be used to determine the height of a tree (iteration must be used).
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A: Question:
please answer 7,8,9
Explanation:
7. a binary tree can have max two child (left and right) in binary (0 or 1)
8. Recursion can also be used to find the number of nodes.
9. Recursion can be used to find the height of a binary tree.
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- Add a function treeLeavesCount, which returns the number of leaves in the binary tree by using a recursive algorithm, to the class binaryTreeType provided (binaryTree.h). Ask the user to enter a list of positive integers ending with -999, build a binary search tree using the positive integers, and display the tree contents after doing inorder, preorder, and postorder traversals. The function treeLeavesCount uses recursion. If the node has an empty left subtree and empty right subtree, add 1 to the count. Otherwise, recursively call the function itself on the left subtree as well as the right subtree. binaryTree.hmy code works the fine the way it is, but I need to add a function for searching for a name and giving the number of probes it took to find a name - while using names that exist in the tree – and at least one that doesn’t. Show the number of probes to reach each node. I’m having a hard time figuring out how to add those. Here is my code: package minas_gil_project_2; import java.io.FileInputStream; import java.io.IOException; import java.util.Scanner; public class BinarySearchTree { private Node head; // head of list public static class Node { String data; Node left; Node right; public Node(String data) { this.data = data; this.left = null; this.right = null; } } public Node root; public BinarySearchTree() { root = null; } public void insert(String data) { Node newNode = new Node(data); if (root == null) { root = newNode;…I have a code that is supposed to output whether a tree is balanced or unbalanced. The input format is id w id_l d_l id_r d_r. I have to store the root of the tree in a variable. import java.util.*;import java.io.*; public class Solution { static class Node { int id; int weight; Node leftChild; Node rightChild; int leftDistance = -1; int rightDistance = -1; public Node(int id, int weight) { this.id = id; this.weight = weight; this.leftDistance = leftDistance; this.rightDistance = rightDistance; } } // Method to read input and create tree public static Node createTree() { Scanner sc = new Scanner(System.in); Map<Integer, Node> map = new HashMap<>(); Node root = null; // check all nodes while (sc.hasNextInt()) { int id = sc.nextInt(); int w = sc.nextInt(); // weight int id_l = sc.nextInt(); // id…
- a) Write a program to construct a BST for a given set of key. b) Search a given key in a given BST. c) Traverse a BST in i) preorder, ii) inorder, iii) postorder. d) Delete a node from the tree with given key (node maybe i) leaf node, ii) it may have one child, iii) it may have two child) Code in C.construct a binary search tree using a set of numbers, similar to the example mentioned in the class. after constructing the BST, you need to give the pre-order traversal of the tree. Finally, you’re required to remove the root of tree. Please show me step by step how to do this!You are creating from scratch a binary search tree class with the methods insert, find, and delete in addition to the method getRandomNode(), which retrieves a random node from the tree. There should be an equal chance of selecting each node. Create a getRandomNode algorithm, put it into practise, and describe how you'd develop the other functions.
- Written in Java The diameter D of a binary tree is defined as the number of nodes on the longest path between any two nodes in the tree. The path may pass through the root, but does not have to. For a given diameter, there may be more than one path which has the longestlength. For example, the following tree has diameter of 5:Write a class that evaluates DAGs that represent arithmetic expressions. Use a vertex-indexed array to hold values corresponding to eachvertex. Assume that values corresponding to leaves have been established. Describe a family of arithmetic expressions with the property that the size of the expression tree is exponentially larger than the size of the corresponding DAG (so the running time of your program for the DAG is proportional to the logarithm of the running time for the tree).Write a program that inserts the following numbers into an initially empty BST such that the treeproduced is equivalent to binary search tree.50 30 25 75 82 28 63 70 4 43 74Hint: Calculate the mean value in method and put that value at the root and recursively build theleft and right subtree.A. Implement a function which, given a node in this binary search tree, prints out themaximum depths of its left and right subtrees.B. Implement a function to find the maximum value of all the nodes in the tree.C. Implement a function that balance the tree using appropriate rotation type and return theroot value.Note: You are not allowed to use any built-in Data Structure classes to implement abovescenario
- I have a code that is supposed to output whether a mobile tree is balanced or unbalanced. The input format is id w id_l d_l id_r d_r. import java.util.*;import java.io.*; public class Solution { static class Node { int id; int weight; Node leftChild; Node rightChild; int leftDistance = -1; int rightDistance = -1; public Node(int id, int weight) { this.id = id; this.weight = weight; this.leftDistance = leftDistance; this.rightDistance = rightDistance; } } // Method to read input and create tree public static Node createTree() { Scanner sc = new Scanner(System.in); TreeMap<Integer, Node> map = new TreeMap<>(); //Map<Node, Node> parentMap = new HashMap<>(); // inputs int id, w, id_l, d_l, id_r, d_r; Node node, leftNode, rightNode; // check all nodes while (sc.hasNextInt()) { id =…Create the Sample class, which has a constructor that accepts an array p[] of double values as an input and supports the following two operations: Return an index i with a probability of p[i]/T (where T is the total of the numbers in p[]) and alter(i, v) to change the value of p[i] to v. Use a full binary tree with an inferred weight of p[i] for each node. Keep the total weight of all the nodes in its subtree in each node. Pick a random number between 0 and T to obtain a random index and use the cumulative weights to select which branch of the subtree to examine. Change the weights of all nodes on the path from the root to i when updating p[i]. Avoid explicit pointers, as we do for heaps.Write a program in C++ to do the following: a. Build a binary search tree, T1. b. Do a postorder traversal of T1 and, while doing the postorder traversal, insert the nodes into a second binary search tree T2. c. Do a preorder traversal of T2 and, while doing the preorder traversal, insert the node into a third binary search tree T3. d. Do an inorder traversal of T3. e. Output the heights and the number of leaves in each of the three binary search trees.