OA Command Prompt C:\exercise>java Exercise12_01 4 + 5 4 + 5 = 9 c:\exercise>java Exercise12_01 4 4 - 5 = -1 C:\exercise>java Exercise12_01 4x - 5 Wrong Input: 4x c:\exercise>.
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Calculator.java, is a simple command-
line calculator. Note the
Write a program with an exception handler that deals with nonnumeric operands;
then write another program without using an exception handler to achieve the
same objective. Your program should display a message that informs the user of
the wrong operand type before exiting
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- compute z= y-√2, #include <iostream>#include <cmath>#include <ios>#include <iomanip>using namespace std; int main() {double x;double y;double z; cin >> x;cin >> y; /* Your code goes here */ cout << fixed << setprecision(2); // This will output only 2 decimal places.cout << z << endl; return 0;}Java Program ASAP ************This program must work in hypergrade and pass all the test cases.********** This program down below does not pass the test cases in Hypergrade as shown in the scheenshot. Please modify it. Also I have provided the code instructions. Thank you import java.io.BufferedReader;import java.io.FileReader;import java.io.IOException;import java.io.InputStreamReader;import java.util.regex.Pattern;import java.util.regex.Matcher;public class WordSeparator { public static void main(String[] args) { try (BufferedReader reader = new BufferedReader(new InputStreamReader(System.in))) { String inputFileName; boolean fileNotFound; System.out.print("Please enter the file name or type QUIT to exit:\n"); do { fileNotFound = false; // Reset fileNotFound flag for each iteration inputFileName = reader.readLine(); if (inputFileName.equalsIgnoreCase("QUIT")) {…C programming: Fill Out the TODO'S IN THE PROGRAM : #include <stdlib.h> // EXIT_ codes#include <stdbool.h> // bool#include <stdio.h> // printf, scanf#include <string.h> // strlen, strcmp#include "udp.h" // udp library#define CLIENT_LISTENER_PORT 4097#define SERVER_LISTENER_PORT 4098#define MAX_CHARS_PER_MESSAGE 80//-----------------------------------------------------------------------------// Main//-----------------------------------------------------------------------------int main(int argc, char* argv[]){char *remoteIp;char *mode;int remotePort;char str[MAX_CHARS_PER_MESSAGE+1];bool quit = false;bool sendMode;// Verify arguments are goodbool goodArguments = (argc == 3);if (goodArguments){remoteIp = argv[1];mode = argv[2];goodArguments = (strcmp(mode, "server") == 0) || (strcmp(mode, "client") ==0);}if (!goodArguments){printf("usage: chat IPV4_ADDRESS MODE\n");printf(" where:\n");printf(" IPV4_ADDRESS is address of the remote machine\n");printf(" MODE is…
- // Prompt user for value to start // Value must be between 1 and 20 inclusive // At command line, count down to blastoff // With a brief pause between each displayed value import java.util.*; public class DebugSix3 { publicstaticvoidmain(String[] args) { Scanner input =newScanner(System.in); String userNumString; int userNum, val; finalint MIN =1; finalint MAX =20; System.out.println("Enter a number between " + MIN + " and " + MAX + " inclusive"); userNumString = input.next(); userNum = Interger.parseInt(userNumString); while(userNum <MIN|| userNum =MAX) { System.out.println("Number out of range" + "\nEnter a number between "+MIN+" and "+MAX+" inclusive"); userNumString = input.next(); userNum = Integer.parse(userNumString); } for(val = userNum; val <0; --val) { System.out.print(val + " "); for(int x =0; x <100000; ++x) for(int y =0; y <10000; ++y); // Adjust these numbers for faster or slower performance } System.out.println("Blastoff!"); } }Write an application that determines whether a phrase entered by the user is a palindrome. A palindrome is a phrase that reads the same backward and forward without regarding capitalization or punctuation. For example, “Dot saw I was Tod”, “Was it a car or a cat I saw?”, and “Madam, I’m Adam” are palindromes. Display the appropriate feedback: You entered a palindrome or You did not enter a palindrome. import java.util.*; public class Palindrome { publicstaticvoidmain(String[] args) { // Write your code here } }Write an application that determines whether a phrase entered by the user is a palindrome. A palindrome is a phrase that reads the same backward and forward without regarding capitalization or punctuation. For example, “Dot saw I was Tod”, “Was it a car or a cat I saw?”, and “Madam, I’m Adam” are palindromes. Display the appropriate feedback: You entered a palindrome or You did not enter a palindrome. import java.util.*; public class Palindrome { public static void main(String[] args) { // Write your code here } }
- 8.1: FrequencyDesign and implement an application that reads an arbitrary number of integers that are in the range 0 to 50 inclusive and counts how many occurrences of each are entered. After all input has been processed, print all of the values (with the number of occurrences) that were entered one or more times. The output should be one frequency count per line with the following format:3 occurrences of 27 occurrences of 5 SPECIFICATION OF NAMES: Please name your application class FrequencyJava Proram ASAP Please look closely at the circled parts in the failed test case. Improve and adjust the program which is down below with the futher moddifications because it does not pass the test cases in Hypergrade. Please remove /n from the program and for test case 4 after this line: Please re-enter the file name or type QUIT to exit:\n quitENTER there needs to be nothing. Also, I do not need file quit is no found in the program. import java.io.*;import java.util.Scanner;public class ConvertText { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); System.out.println("Please enter the file name or type QUIT to exit:"); while (true) { String input = sc.next(); if (input.compareTo("QUIT") == 0) { break; } else { // Get the absolute path of the current directory String filePath = new File("").getAbsolutePath(); filePath =…only Voicemail.java files can have input added inbetween lines 4 and 7. not in the gery code sections.
- can NOT edit code one grey line (start-4 & 8-end of code) new JAVA code will have to be added in the middle like in the photo.Command line arguments are passed to int main(int argc, char** argv) as arguments argc and argv. You should assume that argc is at ebp+8 and argv is at ebp+12. This program is invoked from the command line as shown: ./program 5 7 The procedure named what is called from main, and returns to main with the value: Options: a) 11 b) 66write in assembly language Divide by two numbers In this assignment, you are required to make an application using assembly code that takes two numbers from the user and returns the result of dividing the first number by the second number. Important notes: 1- You should allow the user to Enter to digits number "For the first number only" 2- You should allow two-digit results if necessary. Stretch goal "optional": Handle the remain of the division process and print it on the screen. Submission: Provide two files (.asm and screenshot). Use your university ID for files naming. Submission status