OA. f(x) = Vx(8 – x) on [0, 8] Sx² + 6x 0< x < 1 1< x < 2 on [0, 1] B. f(x) = { on [0, 2] 8х — 1 OC. f(x) = x6/7 OD. f(x) = x8/9 on [-1, 1] х? — Зх 0< х<1 1< x< 2 0 < x < a E. f(x) = { on [0, 2] 8х — 10 sin(8x) { F. f(x) on [0, n] x = 0 |G. None of the above

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.2: Remainder And Factor Theorems
Problem 51PS
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Which of the following functions satisfy the hypotheses of the Mean Value Theorem on the given interval? (Can you can explain why?)

A. f(x) = Vx(8 – x)
on [0, 8]
}
OC. f(x) = x6/7
x? + 6x
0 < x < 1
1 < x < 2
on [0, 1]
OB. f(x) =
on [0, 2]
В.
8x
-
OD. f(x) = x8/9
on [-1, 1]
E. f(x) = { x – 3x 0<x< 1
on [0, 2]
1< x < 2
0 < x < T
8x
10
-
sin(8x)
F. f(x) =
on [0, x]
x = 0
G. None of the above
Transcribed Image Text:A. f(x) = Vx(8 – x) on [0, 8] } OC. f(x) = x6/7 x? + 6x 0 < x < 1 1 < x < 2 on [0, 1] OB. f(x) = on [0, 2] В. 8x - OD. f(x) = x8/9 on [-1, 1] E. f(x) = { x – 3x 0<x< 1 on [0, 2] 1< x < 2 0 < x < T 8x 10 - sin(8x) F. f(x) = on [0, x] x = 0 G. None of the above
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