# Object B is at rest when object A collides with it. The collision is one-dimensional and elastic. After the collision object B has half the velocity that object A had before the collision.1.) Which object has the greater mass?2.) By how much is the mass of object B greater than that of object A?3.) If the velocity of object A before the collision was 6.0 m/s to the right, what is its velocity after the collision?

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Object B is at rest when object A collides with it. The collision is one-dimensional and elastic. After the collision object B has half the velocity that object A had before the collision.

1.) Which object has the greater mass?

2.) By how much is the mass of object B greater than that of object A?

3.) If the velocity of object A before the collision was 6.0 m/s to the right, what is its velocity after the collision?

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Step 1 help_outlineImage Transcriptionclose(1) The conservation of linear momentum gives, mv mv +m3v2 Here, m is the mass of object A, v is the velocity of object A before collision, v is the velocity of object A after collision, mg is the mass of object B and v, is the velocity of object B after collision It is given that (1) 12 2 Thus, the conservation of momentum equation becomes, (2) m v=m+mB Since the collision is elastic, velocity of approach will be equal to velocity of separation. It is given by, 2- Putting equation (1) in the above equation 2 1 (3) fullscreen

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### Collisions 