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Obtain i, in the instrumentation amplifier circuit of Fig. 5.27. 8.00 v o 40 k2 ww 20 k2 www 20 ka 10 ka 40 k2 8.01 V o- Figure 5.27 Instrumentation amplifier; for Practice Prob. 5.8. Answer: 2 pA.

Obtain i, in the instrumentation amplifier circuit of Fig. 5.27. 8.00 v o 40 k2 ww 20 k2 www 20 ka 10 ka 40 k2 8.01 V o- Figure 5.27 Instrumentation amplifier; for Practice Prob. 5.8. Answer: 2 pA.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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R4 As R3 R Figure 5.26 Instrumentation amplifier; for Example 5.8. Since the op amps Aj and A2 draw no current, current i flows through the three resistors as though they were in series. Hence, Vol - vo2 = i (R3 + R4 + R3) =i (2R3 + R4) (5.8.2) But Va - U i = RA and v, = v1, vh = v2. Therefore, vi - v2 i = R4 (5.8.3) Inserting Eqs. (5.8.2) and (5.8.3) into Eq. (5.8.1) gives R2 Vo = 2R3 + (v2 – v1) R4 as required. We will discuss the instrumentation amplifier in detail in Section 5.10. ROBLEM 5.8 Obtain i, in the instrumentation amplifier circuit of Fig. 5.27. 8.00 V o 40 ka ww- 20 k2 ww- -ww 20 k2 8.01 V o 40 k2 10 kn Figure 5.27 Instrumentation amplifier; for Practice Prob. 5.8. Answer: 2 µA. CНАРТER 5 Operational Amplifiers 181 DED OP AMP CIRCUITS amp circuits are modules or building blocks for designing s. It is often necessary in practical applications to connect in cascade (i.e., head to tail) to achieve a large overall 1, two circuits are cascaded when they are connected in ind another in a single file. ection is a head-to-tail arrangement of two or more op amp circuits uch that the output of one is the input of the next. amp circuits are cascaded, each circuit in the string is the original input signal is increased by the gain of the - Op amp circuits have the advantage that they can be ut changing their input-output relationships. This is due ach (ideal) op amp circuit has infinite input resistance and
Transcribed Image Text:R4 As R3 R Figure 5.26 Instrumentation amplifier; for Example 5.8. Since the op amps Aj and A2 draw no current, current i flows through the three resistors as though they were in series. Hence, Vol - vo2 = i (R3 + R4 + R3) =i (2R3 + R4) (5.8.2) But Va - U i = RA and v, = v1, vh = v2. Therefore, vi - v2 i = R4 (5.8.3) Inserting Eqs. (5.8.2) and (5.8.3) into Eq. (5.8.1) gives R2 Vo = 2R3 + (v2 – v1) R4 as required. We will discuss the instrumentation amplifier in detail in Section 5.10. ROBLEM 5.8 Obtain i, in the instrumentation amplifier circuit of Fig. 5.27. 8.00 V o 40 ka ww- 20 k2 ww- -ww 20 k2 8.01 V o 40 k2 10 kn Figure 5.27 Instrumentation amplifier; for Practice Prob. 5.8. Answer: 2 µA. CНАРТER 5 Operational Amplifiers 181 DED OP AMP CIRCUITS amp circuits are modules or building blocks for designing s. It is often necessary in practical applications to connect in cascade (i.e., head to tail) to achieve a large overall 1, two circuits are cascaded when they are connected in ind another in a single file. ection is a head-to-tail arrangement of two or more op amp circuits uch that the output of one is the input of the next. amp circuits are cascaded, each circuit in the string is the original input signal is increased by the gain of the - Op amp circuits have the advantage that they can be ut changing their input-output relationships. This is due ach (ideal) op amp circuit has infinite input resistance and
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