OCheck that the point (1, 1, 1) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the face and an equation for the tangent plane to the surface at (1, 1, 1). 4x? – y? + 422 = 7

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Vectors In Two And Three Dimensions
Section9.6: Equations Of Lines And Planes
Problem 2E
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Check that the point (1, 1, 1) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the
surface and an equation for the tangent plane to the surface at (1, 1, 1).
4x2 – y? + 4z2 = 7
vector normal = 4x-y+4z
tangent plane:
= Z
7/4-x+1/4y
Transcribed Image Text:Check that the point (1, 1, 1) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (1, 1, 1). 4x2 – y? + 4z2 = 7 vector normal = 4x-y+4z tangent plane: = Z 7/4-x+1/4y
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