OFAT experimentation is less desirable than a full-factorial experiment because the principles and design structure: Gain efficiencies Cost less Save time Miss interactions
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- How many main effects and interaction effects are possible in a 2 × 6 factorial design? No other details given. Statics and reacherce questionsA recent study claims that using music in a class enhances concentration and consequently helps students absorb more information. A researcherdecided to test this claim on a smaller group of randomly selected students from three different classes. Each classroom was provided with a different environment for students to study. Classroom A had constant music being played in the background, classroom B had variable music being played and classroom C was a regular class with no music playing. After one month, the researcher conducted a test for all the three groups and ranked their scores. What statistical test would be most appropriate for testing the research hypothesis? Explain your answer.The researchers reported:" A 2x2 ANOVA revealed, first of all, a main effect for depletion, indicating that depleted individuals generated less ideas (M = 9.40, SD = 5.64) than non-depleted individuals (M = 12.44, SD = 7.34), F (1, 108) = 6.03, p = .016, n2 = .05. This effect was qualified by the expected interaction with [perseverance], F (1,108) = 4.52, p = .036, n2 = .05". What size are the effects for the main effect of depletion and for the interaction between depletion and perseverance, according to Cohen's conventions? a. These are small- to -medium effects b. These are non existent effects c. These are large effects d. We are unable to tell from from the n2 / r2 statistics
- An experimenter is interested in the effects of two independent variables onself-esteem. What is better about conducting a factorial experiment thanconducting two separate experiments, one for each independent variable?A Chi square test has been conducted to assess the relationship between marital status and church attendance. The obtained Chi square is 7.45 and the critical Chi square is 9.488. What may be concluded? Group of answer choices A.reject the null hypothesis, church attendance and marital status are independent B.fail to reject the null hypothesis, church attendance and marital status are independent C.Reject the null hypothesis, church attendance and marital status are dependent D.fail to reject the null hypothesis, church attendance and marital status are dependentIn the simple linear regression model , the Gauss Markov ( classical ) assumptions guarantee that the OLS estimator of the unknown parameters is BLUE. Among those assumptions , in order to have consistency of the OLS estimator we need ( this is a question on the necessary condition ): Question 4Select one: a. we need that the errors are not correlated with each others and that they have zero mean b. we need that the errors are homoscedastic ( all have the same variance) c. we need that the residuals are not correlated with the explanatory variables and that the residuals have zero mean d. we need that the errors have zero mean and that they are not correlated with the regressors ( no endogeneity) e. we need that the errors are homoscedastic ( all have the same variance) and not correlated with each others ( no serial correlation)
- Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices. So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles. To test for independence, we need to calculate the Chi-square statistic. These are the data that Dr. Pagels collected ( the attachment): You will want to use Excel (or Google sheets) to do the calculations for you, so that your answers are exact (they need to be exact to get credit. Here is a Google sheet to get you started. When transferring your answers, make sure you carry them out to AT LEAST SIX SIGNIFICANT FIGURES unless otherwise stated. Round your final answer to 4 decimal…An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more efficiently. Two alternative loading/unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use ? = 0.05. Type of Ride Roller Coaster Screaming Demaon Log Flume Method 1 41 52 50 43 44 46 Method 2 49 50 48 51 46 44 Find the value of the test statistic for method of loading and unloading. Test statistic=?? Find the p-value for method of loading and unloading. (Round your answer to three decimal places.) p-value = ?? State your conclusion about method of loading and unloading. -Because the p-value ≤ ? = 0.05, method…