O(g) + e–(g) --> O–(g)    ∆Hº = –142 kJ mol–1 O(g) + 2 e–(g) --> O 2– (g) ∆Hº = +702 kJ mol–1 What is ∆Hº for the following reaction? O–(g) + e–(g) --> O 2– (g)

Chemistry for Engineering Students
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Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.46PAE: 10.46 Discuss the effect of temperature change on the spontaneity of the following reactions at 1...
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O(g) + e(g) --> O(g)    ∆Hº = –142 kJ mol–1

O(g) + 2 e(g) --> O 2– (g) ∆Hº = +702 kJ mol–1

What is ∆Hº for the following reaction?

O(g) + e(g) --> O 2– (g)

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