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On a coordinate plane, triangle FGH is formed with the vertices at point F(0, -2), point G(1,0), and point H(2, -3). Which expression can be used to determine the perimeter, in units, of triangle FGH? a. (0-1)2 +(-2-0)2 +V(1-2)² + (0 – (-3))² + (2-0)2+(-3-(-2))² b. (0-(-2))2 + (1-0)2 + (1-0)2 + (2- (-3))2 + (2-(-3))2 + (0-(-2))2 c. (0+1)2 - (-2 +0)2 +V(1+ 2)² - (0+ (-3))2 + (2+0)2-(-3+(-2))² d. (0+ (-2))2- (1+0)2 + (1+ 0)2- (2+ (-3))2 + /+(-3))2 - (0+(-2))2

On a coordinate plane, triangle FGH is formed with the vertices at point F(0, -2), point G(1,0), and point H(2, -3). Which expression can be used to determine the perimeter, in units, of triangle FGH? a. (0-1)2 +(-2-0)2 +V(1-2)² + (0 – (-3))² + (2-0)2+(-3-(-2))² b. (0-(-2))2 + (1-0)2 + (1-0)2 + (2- (-3))2 + (2-(-3))2 + (0-(-2))2 c. (0+1)2 - (-2 +0)2 +V(1+ 2)² - (0+ (-3))2 + (2+0)2-(-3+(-2))² d. (0+ (-2))2- (1+0)2 + (1+ 0)2- (2+ (-3))2 + /+(-3))2 - (0+(-2))2

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 70E
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а. 5 b. 10 C. 25 d. 100 5 On a coordinate plane, triangle FGH is formed with the vertices at point F(0, -2), point G(1,0), and point H(2, -3). Which expression can be used to determine the perimeter, in units, of triangle FGH? a. (0-1)2 +(-2-0)2 +(1-2)² + (0-(-3)) + (2-0)2 + (-3-(-2))? (0-(-2)) +(1- 0)2 + V(1-0)2 + (2 - (-3))2 +(2- (-3))2 + (0-(-2))² (0+1)2-(-2+0)2 + V(1 + 2)2 - (0 + (-3))2 +(2+ 0)2 -(-3+ (-2))2 d. (0+(-2))2 - (1+ 0)2 +/(1+ 0)2 - (2+ (-3))2 + V+(-3))2 - (0+(-2))2 b. C. Line segment JK is shown on the graph below. 10 4 12
Transcribed Image Text:а. 5 b. 10 C. 25 d. 100 5 On a coordinate plane, triangle FGH is formed with the vertices at point F(0, -2), point G(1,0), and point H(2, -3). Which expression can be used to determine the perimeter, in units, of triangle FGH? a. (0-1)2 +(-2-0)2 +(1-2)² + (0-(-3)) + (2-0)2 + (-3-(-2))? (0-(-2)) +(1- 0)2 + V(1-0)2 + (2 - (-3))2 +(2- (-3))2 + (0-(-2))² (0+1)2-(-2+0)2 + V(1 + 2)2 - (0 + (-3))2 +(2+ 0)2 -(-3+ (-2))2 d. (0+(-2))2 - (1+ 0)2 +/(1+ 0)2 - (2+ (-3))2 + V+(-3))2 - (0+(-2))2 b. C. Line segment JK is shown on the graph below. 10 4 12
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