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- An ISP has the following block of addresses 132.204.192/20. The manager of this ISP hired you to help him assign IP block of addresses to the following subnets. Subnet A should have enough addresses to support at least 850 interfaces; Subnet B should have enough addresses to support at least 55 interfaces; Subnet C should have enough addresses to support at least 46 interfaces; Subnet D should have enough addresses to support at least 40 interfaces; Subnet E should have enough addresses to support at least 20 interfaces. Subnet F should have enough addresses to support at least 28 interfaces. Give the range of addresses (in binary) assigned to each subnet. Show your work.Consider the following non-default subnet masks: (a) 255.255.248.0, (b) 255.128.0.0 . To which IP address class do they pertain?Write down the following in CIDR notation: (a) IP: 150.160.170.180, Subnet Mask:255.255.224.0; (b) IP: 75.80.85.90, Subnet Mask: 255.252.0.0 Three stations A, B, C and D are connected to a common Ethernet hub. Their IPaddresses and subnet mask are respectively: 200.100.50.67, 255.255.255.252;200.100.50.7, 255.255.255.248; 200.100.50.138, 255.255.255.240 and 200.100.50.1,255.255.255.254. Determine which among these stations can communicate with eachother. You need to show all detailed workings.Computer Science To answer this question, you may need to write a small program. Consider the following case: current cwnd value is 1000 bytes and 1 MSS is 10 bytes (=1 TCP packet carries 10 bytes of payload). With the basic formula, after 1 RTT, the congestion window would be updated to 1010 bytes (1000 + 10). What would be the value of window if ACK clocking is used? It would be a non-integer number, so give value including only two digits after comma
- 59- A network for a local office requires 4 LAN subnets as follows: · Subnet A - North Office with 31 hosts; · Subnet B - East Office with 15 hosts; and · Subnet C - South Office with 7 hosts. · Subnet D – West Office with 4 hosts. Given the IP Address 192.168.15.0 /24 and above described network requirements: 1. Design an optimal address scheme using Variable Length Subnet Mask (VLSM) method What will be the subnet mask of Subnet D? Select one: a. 255.255.255.192 b. 255.255.255.248 c. 255.255.192.192 d. 255.255.192.0 e. 255.255.128.25554- A network for a local office requires 4 LAN subnets as follows: · Subnet A - North Office with 31 hosts; · Subnet B - East Office with 15 hosts; and · Subnet C - South Office with 7 hosts. · Subnet D – West Office with 4 hosts. Given the IP Address 192.168.15.0 /24 and above described network requirements: 1. Design an optimal address scheme using Variable Length Subnet Mask (VLSM) method; and What will be the subnet mask of Subnet B? Select one: A. 255.255.128.255 B. 255.255.192.0 C. 255.255.192.192 D. 255.255.255.192 E. 255.255.255.224Answer the following: a) Rewrite the given IPv4 address using dotted-decimal notation and find the class. 01011110 10110000 01110101 00010101 b) Rewrite the given IPv4 address in binary representation and find the class.
- Suppose that CS=3500h, an instruction JMP [ 5A03CH] occurs which is located at 35555h, what will be the new value of CS and IP, assuming real mode? a. CS=5900 IP=103C b. CS=59000 IP=103C c. CS=6900 IP=EF64 d. CS=69000 IP=EFC4 What is the new value of the IP for an instruction JMP {02DD 3ADCH] which is currently located at addresses 0001 up to 0123? Assume DS=02ADh, privilege level is second to the highest and in protected mode a. IP=002FF b. IP=8ADC c. IP=FFADC d. IP=013CAQ3: Assume the given class C IP Address, 192.168.0.X, where; X is the last two digits of your arid number (For example a student having 19-arid-121 will use ASCII of 21 as X . Apply subnetting of 3 bits and write about: a. Network and Broadcast IP of the subnet in which this IP 192.168.0.X belongs to b. First and last valid IP of the subnet in which this IP 192.168.0.X belongs to. c. Sub-net mask of this IP after subnetting.The last part of Bruce Wayne problem How many of each type of subnet size did you need? Include the unallocated subnet size. /22 /23 /24 /25 /26 /27 /28 /29
- In this exercise, we estimate the CIDR address block requirements for TrendyWidgets Inc. For example, if TrendyWidgets needs about 8,000 IP addresses, you would say that TrendyWidgets needs a /19 CIDR block. This is because a /19 address block uses 19 bits for the network part of the IP address, leaving 32 – 19 = 13 bits available for the host part. This allows unique labeling for 213 = 8,192 hosts. Answer the following questions: 1. If each computer on TrendyWidgets’ network is allocated an IP address, how many IP addresses is TrendyWidgets likely to need? 2. Based on this estimate, what is a CIDR address-block size suitable for TrendyWidgets?Consider the following diagram: A,B,C and D are subnets, R1, R2, and R3 are routers. Default signifies theentire rest of the internet. All 4 subnets each contain the same number of hosts.Consider the following routing table at R3: CIDR Mask Link 0.0.0.0/0 L4 128.4.6.0/24 L3 128.4.8.0/24 L5 1. If 128.4.6.0 is in A, what is the routing table at R1? 2. The ISP that owns all these networks is short on IP addresses, so theyuse a NAT router for R2. How many public IP addresses will C andD use together assuming they use as many private 10.X IP addresses asthey can? How many total public IP addresses will be used by the entirenetwork? Why doesn’t the ISP care about how many private IP addressesare used? 3. Fix R3’s routing table now that we are using NAT: 4. A node in C is given the IP address 10.0.0.1 and only sends and receivespackets on port 1234. A packet destined for this node reaches R2 witha source of (IP=128.4.6.6, Port=3000) and destination of (IP=128.4.8.0,Port=10000).…A large number of consecutive IP addresses are available starting at 198.16.0.0. Sup- pose that four organizations, A, B, C, and D, request 4000, 2000, 4000, and 8000 ad- dresses, respectively, and in that order. For each of these, give the first IP address as- signed, the last IP address assigned, and the mask in the w.x.y.z/s notation. A router has just received the following new IP addresses: 57.6.96.0/21, 57.6.104.0/21, 57.6.112.0/21, and 57.6.120.0/21. If all of them use the same outgoing line, can they be aggregated? If so, to what? If not, why not? The set of IP addresses from 29.18.0.0 to 19.18.128.255 has been aggregated to 29.18.0.0/17. However, there is a gap of 1024 unassigned addresses from 29.18.60.0 to 29.18.63.255 that are now suddenly assigned to a host using a different outgoing line. Is it now necessary to split up the aggregate address into its constituent blocks, add the new block to the table, and then see if any reaggregation is possible? If not, what can be…