One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following unbalanced chemical equation: Rh2(SO4)3(aq) + NaOH(aq)  →  Rh(OH)3(s) + Na2SO4(aq) If 3.10 g of rhodium(III) sulfate reacts with 5.90g of sodium hydroxide  a. Determine the limiting reactant.  b. Determine the excess reactant.  c. What mass of rhodium (III) Hydroxide  may be produced  d. Calculate the percent yield if 1.3 g of rhodium (III) Hydroxideare actually obtained.  MM of  Rh2(SO4)3(aq) = 494g/mol MM of NaOH =  40g/mol) MM of  Rh(OH)3(s) = 153.93g/mo

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".