S y = 3 – a 4z – 4 = 3(x + 1)²

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.1: Simplifying Fractions
Problem 38WE
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Consider the surface S: y = 3 - x3, in the first octant and bounded by 4z - 4 = 3 (x + 1)2 and z = 4, as shown in the figure.

(see attached image)

The area of S, in linear units squared, corresponds to:
A) A (S) ≈ 1.542
B) A (S) ≈ 1,250
C) A (S) ≈ 2,021
D) A (S) ≈ 1.498

 

S
y = 3 – 23
4z – 4 = 3(x + 1)²
Transcribed Image Text:S y = 3 – 23 4z – 4 = 3(x + 1)²
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