Oppositely charged parallel plates are separated by 4.85 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? 1.25*10**5 v N/C (b) What is the magnitude of the force on an electron between the plates? -600 |× N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.48 mm from the positive plate? |-1.39

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter7: Electric Potential
Section: Chapter Questions
Problem 37P: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50104...
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Oppositely charged parallel plates are separated by 4.85 mm. A potential difference of 600 V exists between the plates.
(a) What is the magnitude of the electric field between the plates?
1.25*10**5
V N/C
(b) What is the magnitude of the force on an electron between the plates?
|-600
X N
(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.48 mm from the positive plate?
-1.39
Transcribed Image Text:Oppositely charged parallel plates are separated by 4.85 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? 1.25*10**5 V N/C (b) What is the magnitude of the force on an electron between the plates? |-600 X N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.48 mm from the positive plate? -1.39
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